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seropon [69]
3 years ago
14

Describe a situation where an object has a change in velocity but constant speed

Physics
2 answers:
arlik [135]3 years ago
8 0
-- the little ball going round and round a spinning roulette wheel

-- a car driving around a curve in the road at a constant speed

-- any Earth satellite in a perfectly circular orbit.
The closest thing to it is a geostationary TV satellite ... they try hard
to make those orbits perfectly circular, and keep correcting them to
stay circular.
valkas [14]3 years ago
7 0
Speed does not depend on direction, but velocity does. 

So, when their is a direction, the velocity would change, but speed would remain constant. <span />
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"Giant Swing", the seat is connected to two cables as shown in the figure (Figure 1) , one of which is horizontal. The seat swin
Bingel [31]
The horizontal force is m*v²/Lh, where m is the total mass. The vertical force is the total weight (233 + 840)N. 

<span>Fx = [(233 + 840)/g]*v²/7.5 </span>

<span>v = 32.3*2*π*7.5/60 m/s = 25.37 m/s </span>

<span>The horizontal component of force from the cables is Th + Ti*sin40º and the vertical component of force from the cable is Ta*cos40º </span>

<span>Thh horizontal and vertical forces must balance each other. First the vertical components: </span>

<span>233 + 840 = Ti*cos40º </span>

<span>solve for Ti. (This is the answer to the part b) </span>

<span>Horizontally </span>

<span>[(233 + 840)/g]*v²/7.5 = Th + Ti*sin40º </span>

<span>Solve for Th </span>

<span>Th = [(233 + 840)/g]*v²/7.5 - Ti*sin40º </span>

<span>using v and Ti computed above.</span>
3 0
3 years ago
Stars seen in the night sky appear to move ____ relative to polaris.
Fed [463]

The answer is counter clockwise relative to the polaris. The polaris, also known as northern star would seem a bit more stable on the night sky as the point of vision is up north, the stars however around this would look as if it was rotating, left to right but since the earth is round in shape it follows a circular pattern.

5 0
3 years ago
A wooden cylinder of length L and cross-sectional area A is partially submerged in a liquid with the axis of the cylinder orient
SCORPION-xisa [38]

Answer:

F=\rho_LAdg

Explanation:

The buoyant force F is equal to the weight of the displaced fluid. The weight of the displaced fluid is W=m_dg, where m_d is the mass of the displaced fluid. The mass of the displaced fluid is m_d=\rho_LV_d, where \rho_L is the density of the fluid and V_d is the displaced volume, which is equal to the submerged volume of the cilinder V_d=V_s=Ad.

Putting all together we have:

F=W=m_dg=\rho_LV_dg=\rho_LAdg

7 0
4 years ago
Jalen combines two substances in science class. Once combined, only one of the two substances
dusya [7]

Answer: b. The combination is a mixture because the substances can be separated

Explanation: Based on the facts presented above, the combination of both both substances can be referred to as a mixture due to the following:

A mixture is obtained when two or more substances or materials are combined without a chemical reaction. This is observed when Jalen combined substance 1 and 2 with only one of the substances becoming visible after the combination.

The other reason is that, a mixture can be separated back into its original constituent, this is evident when the combination was filtered with only substance 2 going through the filter and substance 1 remaining in the filter

4 0
3 years ago
A heavier mass m1 and a lighter mass m2 are 17.0 cm apart and experience a gravitational force of attraction that is 9.70 10-9 N
puteri [66]

Answer:

The value of m1 is 4.2 kg and value of m2 is 1 kg.

Explanation:

Note:- The value of force is assumed to be 9.70*10^-9 N.

The gravitational force F is given by the formula,

F=Gm1m2 / r^2

where F is the force, G is the universal gravitational constant, m1 and m2 are masses and r is the distance between the masses.

Then the product of the masses is,

m1m2= Fr^2/G

Given F=9.70*10^-9 N, r is 17.0 cm which is equal to 0.17 m.

Therefore product m1m2= 9.70*10^-9 N *(0.17 m)^2 / 6.67*10^(-11) N m^2 kg^-2

m1m2= 4.20 kg^2

m1=4.20 kg^2/m2

The sum of masses is m1+m2=5.20 kg

 4.20/m2+m2=5.20

(m2)^2-5.20m2-4.20=0

After solving the above quadratic equation, mass m2 has values 4.2 kg and 1 kg.

By using m2=1 kg, m1 has greater mass 4.2 kg.

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4 0
2 years ago
Read 2 more answers
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