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3 years ago

Describe a situation where an object has a change in velocity but constant speed

2 answers:

8 0

-- the little ball going round and round a spinning roulette wheel

-- a car driving around a curve in the road at a constant speed

-- any Earth satellite in a perfectly circular orbit.
The closest thing to it is a geostationary TV satellite ... they try hard
to make those orbits perfectly circular, and keep correcting them to
stay circular.

valkas [14]3 years ago

7 0

Speed does not depend on direction, but velocity does.

So, when their is a direction, the velocity would change, but speed would remain constant. <span />

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An object is placed 10 m to the left of a convex lens with a focal length of +8 cm Where is the image of the object

Pani-rosa [81]

Answer:

18 cm to the right

Explanation:

I don't really know i'm just guessing. hope it's right.

3 0

3 years ago

PLEASE HELP URGENT 10 points

melamori03 [73]

Answer:

Both have the same amount. C.

Explanation:

3 0

3 years ago

For the following elementary reaction 2br• -> br2-. The rate of consumption of the reaction and the rate of formation of prod

Scorpion4ik [409]

Answer: $-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}$

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

$2Br^.\rightarrow Br_2$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$Rate=-\frac{d[Br^.]}{2dt}$

or $Rate=+\frac{d[Br_2]}{dt}$

Thus $-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}$

4 0

3 years ago

Gravity is the attractive pull between two objects that have mass. The strength of the gravitational distance. As distance betwe

Mumz [18]

Graph A best represents the relationship between pull is doubled, gravity and distance. depends on the mass and the force of gravity. Option A is correct.

<h3>What is Newton's law of gravity?</h3>

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

The expression for the gravitational force is given as;

$\rm F = G\frac{Mm}{r^2}$

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Decreasing the distance would increase the gravity of the planet.

Gravity is the attraction force that draws two mass-containing objects together. the gravitational distance's strength.

The force of gravity weakens as the distance between the items rises. if the separation is just one-fourth as great as previously. In the graph, the link between pull and doubled is best represented by A.

Hence option A is correct.

To learn more about Newton's law of gravity refer to the link;

brainly.com/question/13428472

#SPJ1

4 0

3 years ago

A father racing his son has 1/4 the kinetic energy of the son, who has 1/3 the mass of the father. The father speeds up by 1.2 m

sergejj [24]

Answer:

Explanation:

KE_s: Kinetic Energy Son

KE_f: Kinetic Energy Father.

Relationship

KE_f: = (1/4) KE_s

m_s: = (1/3) m_f

v_f: = velocity of father

v_s: = velocity of the son

Relationship

1/2 mf (v_f + 1.2)^2 = 1/2 m_s (v_s)^2 Multiply both sides by 2.

mf (v_f + 1.2)^2 = m_s * (v_s)^2 Substitute for the mass of the m_s

mf (v_f + 1.2)^2 = (m_f/3) * (v_s)^2 Divide both sides by father's mass

(v_f + 1.2)^2 = 1/3 * (v_s)^2 multiply both sides by 3

3*(v_f + 1.2)^2 = (v_s) ^2 Take the square root both sides

√3 * (v_f + 1.2) = v_s

Note

You should work your way through all the cancellations to find the last equation shown about
We have another step to go. We have to use the first relationship to get the final answer.

KE_f = (1/4) KE_s Multiply by 4

4* KE_f = KE_s Substitute (again)

4*(1/2) m_f (v_f + 1.2)^2 = 1/2* (1/3)m_f *v_s^2 Divide by m_f

2* (v_f + 1.2)^2 = 1/6 * (v_s)^2 multiply by 6

12*(vf + 1.2)^2 = (v_s)^2 Take the square root

2*√(3* (v_f + 1.2)^2) = √(v_s^2)

2*√3 * (vf + 1.2) = v_s

Use the second relationship to substitute for v_s so you can solve for v_f

2*√3 * ( v_f + 1.2) = √3 * (v_f + 1.2) Divide by sqrt(3)

2(v_f + 1.2) = vf + 1.2

Edit

2vf + 2.4 = vf + 1.2

2vf - vf + 2.4 = 1.2

vf = 1.2 - 2.4

vf = - 1.2

This answer is not possible, but 2 of us are getting the same answer. The other person is someone whose math I would never question. She rarely makes an error. And I do mean rarely. Could you check to see that you have copied this correctly?

5 0

4 years ago