Answer:
the resistance of the second wire is 1 ohm.
Explanation:
Given;
cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²
resistance of the first wire, R₁ = 1.75 ohms
cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²
resistance of the second wire, R₂ = ?
The resistance of a wire is given as;
R ∝ 
Since the length of the two wires is constant
R₁A₁ = R₂A₂
Therefore, the resistance of the second wire is 1 ohm.
Answer:
6.25 mph
Explanation:
You would divide 25 by 4 to get the average miles per hour.
Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
The first experiment that was made to attempt to measure the speed of light involved detonating gunpowder by Isaac Beeckman. He declared that his experiment was inconclusive. Galileo also tried to measure the speed of light using two lanterns placed across each other. The next experiment involved planets where Ole Romer based his calculation on its movements. The final calculations were derived from different theories by different scientists including Maxwell until it ended up with the exact value for the speed of light.
Answer: The acceleration will be greater in the kickball than the soccer ball since the kick ball has a smaller mass and provided they are acted upon with equal force magnitude.
Explanation:
We can prove this by substituting with numerical values.
Say the force she kicked both balls with was 30 N. The mass of the soccer ball is 10kg and the mass of the kickball is 6kg.
Applying Newtons Second Law, F = ma
For the soccer ball:
30 = 10a
a = 30/10
a = 3
For the kickball:
30 = 6a
a = 30/6
a = 5
Hence the kickball will travel with a greater acceleration given the same force is acted upon and has a smaller mass than the soccer ball
Hope this helps, brainliest would be appreciated :)
