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Georgia [21]
4 years ago
15

A wooden cylinder of length L and cross-sectional area A is partially submerged in a liquid with the axis of the cylinder orient

ed straight up and down. The density of the liquid is rhoL. If the length of the cylinder that is below the surface of the liquid is d, what is the buoyant force that the liquid exerts on the cylinder? (Ignore the small buoyant force exerted by the air on the part of the cylinder above the surface of the liquid.)
Physics
1 answer:
SCORPION-xisa [38]4 years ago
7 0

Answer:

F=\rho_LAdg

Explanation:

The buoyant force F is equal to the weight of the displaced fluid. The weight of the displaced fluid is W=m_dg, where m_d is the mass of the displaced fluid. The mass of the displaced fluid is m_d=\rho_LV_d, where \rho_L is the density of the fluid and V_d is the displaced volume, which is equal to the submerged volume of the cilinder V_d=V_s=Ad.

Putting all together we have:

F=W=m_dg=\rho_LV_dg=\rho_LAdg

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How do hydrogen bonds affect boiling points?
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A bird on a long migration flies 63 kilometers per hour for 2900
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Answer:

46

Explanation:

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5 0
3 years ago
2. A pair of narrow, parallel slits sep by 0.25 mm is illuminated by 546 nm green light. The interference pattern is observed on
Agata [3.3K]

Answer:

for the first interference m = 1   y = 2,839 10-3 m

for the second interference m = 2   y = 5,678 10-3 m

Explanation:

The double slit interference phenomenon, for constructive interference is described by the expression

                d sin θ = m λ

where d is the separation between the slits, λ the wavelength and m an integer that corresponds to the interference we see.

In these experiments in general the observation screen is L >> d, let's use trigonometry to find the angles

           tan θ = y / L

with the angle it is small,

          tan θ = sin θ / cos θ = sin θ

   

we substitute

         sin θ = y / L

         d y / L = m λ

the distance between the central maximum and an interference line is

        y = m λ L / d

let's reduce the magnitudes to the SI system

     λ = 546 nm = 546 10⁻⁹ m

     d = 0.25 mm = 0.25 10⁻³ m

let's substitute the values

      y = m 546 10⁻⁹ 1.3 / 0.25 10⁻³

      y =  m 2,839 10⁻³

the explicit value for a line depends on the value of the integer m, for example

for the first interference m = 1

the distance from the central maximum to the first line is y = 2,839 10-3 m

for the second interference m = 2

the distance from the central maximum to the second line is y = 5,678 10-3 m

3 0
3 years ago
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