A wooden cylinder of length L and cross-sectional area A is partially submerged in a liquid with the axis of the cylinder orient
1 answer:
Answer:
Explanation:
The buoyant force F is equal to the weight of the displaced fluid. The weight of the displaced fluid is , where
is the mass of the displaced fluid. The mass of the displaced fluid is
, where
is the density of the fluid and
is the displaced volume, which is equal to the submerged volume of the cilinder
.
Putting all together we have:
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The elastic potential energy of a spring is given by
where k is the spring's constant and x is the displacement with respect to the relaxed position of the spring.
The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:
In our problem, initially the spring is uncompressed, so
. Therefore, the work done by the spring when it is compressed until 
is
And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.
where k is the spring's constant and x is the displacement with respect to the relaxed position of the spring.
The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:
In our problem, initially the spring is uncompressed, so
And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.
Answer:
The tension is
Explanation:
The free body diagram of the question is shown on the first uploaded image From the question we are told that
The distance between the two poles is
The mass tied between the two cloth line is
The distance it sags is
The objective of this solution is to obtain the magnitude of the tension on the ends of the clothesline
Now the sum of the forces on the y-axis is zero assuming that the whole system is at equilibrium
And this can be mathematically represented as
To obtain we apply SOHCAHTOH Rule
So
