The Normal Force = M x G x Cos(theta)
= 9.5 Kg x 9.8 m/s^2 x cos 23
= 9.5 Kg x 9.8 m/s^2 x 0.9205
Converting Kg to Newton,
1 Kg = 9.81 N
= 9.5 Kg x 9.81 N x 9.8 m/s^2 x 0.9205
= 840.702 N
Answer:
Va = 5000 m / 3600 s = 1.39 m/s
(Va - Vb) 60 = 10
Vb = Va - .167 = 1.22 m/s
(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap
.17 T = 4200 Π
T = 24700 Π time for A to again catch B
N = 1.39 * 24700 Answer:
Va = 5000 m / 3600 s = 1.39 m/s
(Va - Vb) 60 = 10
Vb = Va - .167 = 1.22 m/s
(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap
.17 T = 4200 Π
T = 24700 Π time for A to again catch B
N = 1.39 * 24700 Π / (4200 Π) = 8.2 laps
A will make 8 but not 9 rounds before catching B
Answer:
i think the answer is 50 kW.h
Answer:
100 J
Explanation:
Given:
Force acting on the crate is, 
Displacement of the crate is, 
Angle between the direction of force and displacement is, 
Now, work done by a force 'F' causing a displacement 'S' such that the angle between the force and displacement is 
is given as:
Now, plug in 100 N for 'F', 2 m for 'S', and 60° for . This gives,
Therefore, the work done by the force is 100 J.
C.) The rougher the surface of an object, the more friction it will produce.
think of sliding a rock on the street
