Calculate the weight of Fe3O4 in 100.0g Fe2O3.

Chemistry

1 answer:

avanturin [10]3 years ago

4 0

Answer:

96.66 g of Fe₃O₄

Explanation:

In order to calculate the weight of Fe₃O₄ in 100.0 g of Fe₂O₃ we need elements in common between both substances, for instance, the mass of Fe in each one. We will use the molar mass of Fe = 55.84g/mol The conversion factors we need are:

159.69 g of Fe₂O₃ contain 2 × 55.84 = 111.68 g of Fe

231.54 g of Fe₃O₄ contain 3 × 55.84 = 167.52 g of Fe

Then, we can use proportions:

$100.0gFe_{2}O_{3}.\frac{111.68gFe}{159.69gFe_{2}O_{3}} .\frac{231.54gFe_{3}O_{4}}{167.52gFe} =96.66gFe_{3}O_{4}$

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