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3 years ago

Calculate the weight of Fe3O4 in 100.0g Fe2O3.

Chemistry

1 answer:

avanturin [10]3 years ago

4 0

Answer:

96.66 g of Fe₃O₄

Explanation:

In order to calculate the weight of Fe₃O₄ in 100.0 g of Fe₂O₃ we need elements in common between both substances, for instance, the mass of Fe in each one. We will use the molar mass of Fe = 55.84g/mol The conversion factors we need are:

159.69 g of Fe₂O₃ contain 2 × 55.84 = 111.68 g of Fe

231.54 g of Fe₃O₄ contain 3 × 55.84 = 167.52 g of Fe

Then, we can use proportions:

$100.0gFe_{2}O_{3}.\frac{111.68gFe}{159.69gFe_{2}O_{3}} .\frac{231.54gFe_{3}O_{4}}{167.52gFe} =96.66gFe_{3}O_{4}$

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how do i solve these equations using proust's law? we haven't gone over balancing chem equations in class and our teacher doesn'

kow [346]

Answer:

Explanation:

Ok so Proust's Law, better known as the Law of Definite Proportions, states that the components of a compound always exist in a fixed ratio. This means that it does not matter what the source of the components are nor the coefficients in front of them. The ratio your teacher is referring to is most likely mass percent/ percent composition. This ratio is the amount of the component over the amount of the entire compound times 100%.

*I am not very familiar with this law so please do with my answers what you will :)*

7.)

First, you want to find the percent composition (aka mass composition) of Na in NaCl.

45.89 g Na
--------------------- x 100% = 39.3%
116.89 g NaCl

So, there must be 39.3% sodium in NaCl. You can find how much chlorine is in NaCl by subtracting that percent by 100 (to find the percent composition of chlorine) then multiplying it by the mass.

100% - 39.3% = 60.7%

60.7% / 100 = 0.0607

116.89 g NaCl x 0.0607 = 70.91 g Cl₂

You could also just subtract the mass of sodium from the mass of sodium chloride to find the mass of chlorine.

116.89 g NaCl - 45.89 g Na = 71 g Cl₂

8.)

10.57 g Mg + 6.96 g O₂ = 17.53 g MgO

6.96 g O₂
--------------------- x 100% = 39.7% O₂
17.53 g MgO

9.)

6.46 g Pb = 1 g O₂

68.54 g Pb = 28.76 g O₂

68.54 g Pb / 28.76 g O₂ = 2.83 g ≠ 6.46 g

No, the two samples are not the same because the proportion of lead to oxygen is not the same for both samples. In the first sample, there is 6.46 g lead for every oxygen. In the second sample, there is 2.38 g lead for every oxygen.

6 0

2 years ago

The existence of discrete (quantized) energy levels in an atom may be inferred from

AURORKA [14]

<span>It can be inferred from atomic line spectra. These are certain wavelengths of light that atoms give off when they become excited. The energy levels in an atom can be proven to exist from this phenomenon, and furthermore, they can be measured.</span>

8 0

3 years ago

Draw the skeletal (line-angle) structure for 2,2-dimethyl-4-propyloctane.

Allisa [31]

Answer :

Total carbons are in the structure = 13

Primary carbons are in the structure = 5

Secondary carbons are in the structure = 6

Tertiary carbons are in the structure = 1

Quaternary carbons are in the structure = 1

Explanation :

Primary carbon : It is a carbon atom that is bound to only 1 carbon atom.

Secondary carbon : It is a carbon atom that is bound to 2 carbon atom.

Tertiary carbon : It is a carbon atom that is bound to 3 carbon atom.

Quaternary carbon : It is a carbon atom that is bound to 4 carbon atom.

As we are given the name of compound is, 2,2-dimethyl-4-propyloctane.

In this compound, eight carbon are align in a straight line, two methyl group are attached at 2nd position of the carbon in main chain and a propyl group that is three membered carbon chain is attached at 4th position of the carbon in main chain.

The given compound skeletal structure is shown below.