How much heat is released when you condense 93.9 g of water vapor? Show work please ❤️
1 answer:
<u>Answer:</u>
211.9 J
<u>Explanation:</u>
The molecules of water release heat during the transition of water vapor to liquid water, but the temperature of the water does not change with it.
The amount of heat released can be represented by the formula:
where = heat energy,
= mass of water and
= latent heat of evaporation.
The latent heat of evaporation for water is and the mass of the water is
.
The amount of heat released in this process is:
211.9 J
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Answer:
1.12M
Explanation:
Given parameters:
Volume of solution = 2.5L
Mass of Calcium phosphate = 600g
Unknown:
Concentration = ?
Solution:
Concentration is the number of moles of solute in a particular solution.
Now, we find the number of moles of the calcium phosphate from the given mass;
Formula of calcium phosphate = Ca₃PO₄
molar mass = 3(40) + 31 + 4(16) = 215g/mol
Number of moles of Ca₃PO₄ = = 2.79moles
Now;
Concentration =
Concentration = = 1.12M
Answer:
0.5 moles of LiOH will absorb 5.6 L of
Explanation:
According to law of conservation of mass, the sum of mass on the reactant side must be equal to the sum of mass on product side.
The balanced chemical equation is:
2 moles of LiOH absorb 1 mole of i.e. 22.4 Liters at STP
0.5 moles of LiOH absorb
=
0.5 moles of LiOH will absorb 5.6 L of