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MatroZZZ [7]
3 years ago
7

FREE POINTS no question

Chemistry
2 answers:
Dima020 [189]3 years ago
6 0

Answer:

Thank you so much!

Explanation:

Crazy boy [7]3 years ago
5 0

Answer:

you are very welcome Brainly is here for you

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What would happen if the cell cycle stopped in a multicellular organism
oksano4ka [1.4K]

The organism would no longer grow.

5 0
3 years ago
Características de la báscula granataria porfi
saveliy_v [14]

Answer:

Lowkey dont know the language

Explanation:

3 0
3 years ago
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
3 years ago
Density is a derived unit of mass / volume.
lapo4ka [179]

Answer:

1kg/L

Explanation:

1.) convert grams to kilograms

1000g÷1000=1kg

2.)use formula to find density

density =  \frac{mass}{volume}

= 1kg/1.0L

=1kg/L

6 0
2 years ago
Calculate the [oh−] in a solution with a ph of 12.52.
BaLLatris [955]
PH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M
6 0
3 years ago
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