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stiks02 [169]
3 years ago
13

A pizza place offers 4 different cheeses and 10 different toppings. In how many way

Mathematics
1 answer:
babymother [125]3 years ago
4 0

Answer:

840

Step-by-step explanation:Explanation:

Picking 1 cheese from 4 =  

4 C 1

Picking 4 toppings from 10 =  

10 C 4

Combining the two:  

4 C 1 ⋅ 10 C 4

=

4 ⋅ 210

=840

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A hat factory makes 2 types of hats. Each day, the factory makes 400 of each type of hat. How many hats does the factory make ea
Lostsunrise [7]
The factory makes a total of 800 hats
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3 years ago
3 + 10.8 is:<br> rational<br> irrational<br> Idk what this is if u could please help me
ratelena [41]

Answer:

3 + 10.8 is : rational.

Step-by-step explanation:

the reason for this is because it is neither a variable, pi, or numbers like square root 2.

4 0
3 years ago
PLEASE HELP WITH #6 and #8, DUE SOON!!
Oliga [24]

how do i answer that I don't even know that sorry

3 0
3 years ago
Read 2 more answers
Can you help me please?
PilotLPTM [1.2K]

Answer:

Your answer should be 0.125

Step-by-step explanation:

Divide the numerator by the denominator

1 divided by 8 = 0.125


I see you're from k12. Hello, fellow homeschooler. Good luck on the assignment!

5 0
3 years ago
In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
3 years ago
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