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BlackZzzverrR [31]
3 years ago
15

One angle of a triangle is 50 degrees greater than the smallest​ angle, and the third angle is 10 degrees less than twice the sm

allest angle. find the measures of the three angles.
Mathematics
2 answers:
GarryVolchara [31]3 years ago
7 0
By the Triangle Angle-Sum theorem, the angles of a triangle add up to 180, no matter what kind of a triangle it is.  Now we just have to determine how to identify each angle according to the info we have.  It looks like all 3 angles are dependent upon the measure of the smallest angle, so we will call the smallest angle x.  The second angle is 50 degrees more than the smallest, so the second angle is x + 50.  The third angle is 10 degrees less than 2 times the smallest angle, so the third angle is 2x-10.  We will add all those together and set them equal to 180.  x+x+50+2x-10=180.  Combining like terms we have 4x+40=180, and 4x = 140.  x = 35.  So the smallest angle measures 35.  The second one is 50 more, so the second one is 85.  The third one is 10 less than twice the smallest, so the third angle is 60.  Add those results together and make sure they come to 180.  They do!
tia_tia [17]3 years ago
6 0
All 3 angles of a triangle must equal to 180. You can simply set up an equation to solve this and set it equal to 180.

Angle 1 - 50 + x
Angle 2 - x
Angle 3 - 2x -10

50+x+x+2x-10=180
4x+40=180
4x=140
x=35

Angle 1 = 50+35= 85
Angle 2 = 35
Angle 3 = 2(35) - 10 = 60

60+35+85=180

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Read 2 more answers
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Answer:

B. Yes, because P(X ≥ 68) ≤ .05

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The probability of a score X occuring is said to be unusually high if the probability of a score of X or larger is lower than 5%.

For each student, there are only two possible outcomes. Either they think that the court shows too much concern for criminals, or they do not think this. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Three out of four students said that courts show too much concern for criminals. This means that p = \frac{3}{4} = 0.75

Would 68 be considered an unusually high number of students who feel that courts are partial to criminals?

We have to find P(X \geq 68).

P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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So

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P(X \geq 68) is lower than 0.05, so this is an unusually high number.

So the correct answer is:

B. Yes, because P(X ≥ 68) ≤ .05

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