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Amiraneli [1.4K]
3 years ago
14

Estimated the sum 97,991 + 102,489 _ + _ = _

Mathematics
1 answer:
Firlakuza [10]3 years ago
4 0
97990+102490=200480
First round down 1 and second round up 1 = so it equals out and the result is exact.
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At an animal shelter there are 15dogs, 12 cats, 3 snakes and 5 parakeets . What percent of the number of cats is the number of d
madreJ [45]
Total number of animals at the shelter = 15 + 12 +3 + 5 = 35 animals.
Let the total number of animals be represented by 100%
There are 15 dogs and 12 cats so:
% Number of dogs  = 15/35 x 100% = 42.86%
% Number of cats  = 12/35 x 100%  =  34.28%

6 0
3 years ago
Pls help me and i will know if it is wrong
DENIUS [597]

9514 1404 393

Answer:

  90 miles

Step-by-step explanation:

Let d represent the distance to Grandma's house.

The speed going was ...

  speed = distance/time

  speed = d/2

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  speed = d/2.25

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  d/2 -d/2.25 = 5

  2.25d -2d = 5(4.50) . . . . . multiply by 4.50

  0.25d = 22.5 . . . . . . . . . . .simplify

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Grandma's house is 90 miles away.

8 0
3 years ago
Please help me on this problem
kirill115 [55]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
What is the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81?
Marizza181 [45]

Answer: d. 1.3333

Step-by-step explanation:

We know that the standard error of a sampling distribution is given by :-

S.E.=\dfrac{\sigma}{\sqrt{n}}

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AS per given , we have

\sigma =12

n=81

Then, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 will be :-

S.E.=\dfrac{12}{\sqrt{81}}

=\dfrac{12}{\sqrt{9^2}}=\dfrac{12}{9}\\\\=\dfrac{4}{3}\\\\\approx1.3333

Hence, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 is 1.3333.

Thus the correct answer is d. 1.3333 .

6 0
3 years ago
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Flauer [41]
1 is the median

0000(1)2234

The median is the middle number
4 0
3 years ago
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