Answer:
heat energy
Explanation:
water in the sun begins to get hot
Answer: 
Explanation: For the given reaction:
![Kc=\frac{[Zn^+^2]}{[Ag^+]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BZn%5E%2B%5E2%5D%7D%7B%5BAg%5E%2B%5D%5E2%7D)
Concentrations of the ions are not given so we need to think about another way to calculate Kc.
We can calculate the free energy change using the standard cell potential as:

can be calculated using standard reduction potentials.
Standard reduction potential for zinc is -0.76 V and for silver, it is +0.78 V.
= 
Reduction takes place at anode and oxidation at cathode. As silver is reduced, it is cathode. Zinc is oxidized and so it is anode.
= 0.78 V - (-0.76 V)
= 0.78 V + 0.76 V
= 1.54 V
Value of n is two as two moles of electrons are transferred in the cell reaction F is Faraday constant and its value is 96485 C/mol of electron .

= -297173.8 J
Now we can calculate Kc using the formula:

T = 25+273 = 298 K
R = 
--297173.8 = -(8.314*298)lnKc
297173.8 = 2477.572*lnKc

lnKc = 119.946


Answer:
activation energy would be your answer here
Explanation:
<u>Given:</u>
Mass of Ag = 1.67 g
Mass of Cl = 2.21 g
Heat evolved = 1.96 kJ
<u>To determine:</u>
The enthalpy of formation of AgCl(s)
<u>Explanation:</u>
The reaction is:
2Ag(s) + Cl2(g) → 2AgCl(s)
Calculate the moles of Ag and Cl from the given masses
Atomic mass of Ag = 108 g/mol
# moles of Ag = 1.67/108 = 0.0155 moles
Atomic mass of Cl = 35 g/mol
# moles of Cl = 2.21/35 = 0.0631 moles
Since moles of Ag << moles of Cl, silver is the limiting reagent.
Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles
Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol
Ans: Formation enthalpy = 126.5 kJ/mol
Answer:- molar mass of the unknown gas is 71.5 gram per mol.
Solution:- From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.
When we compare the effusion rates of two gases then the formula for Graham's law is:

In this formula, V stands for volume and M stands for molar mass
Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:

let's say in formula, subscript 1 is for hydrogen gas and 2 is for the unknown gas.
Molar mass of hydrogen is 2.02 grams per mol and the time taken to effuse it is 2.42 min. The time taken to effuse the unknown gas is 14.4 min and we are asked to calculate it's molar mass. let's plug in the values in the formula:


doing squares to both sides:



So, the molar mass of the unknown gas is 71.5 grams per mol.