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tresset_1 [31]
3 years ago
11

What type of energy does water gain as it sits in the sun?

Chemistry
2 answers:
Studentka2010 [4]3 years ago
8 0

Answer:

heat energy

Explanation:

water in the sun begins to get hot

Dennis_Churaev [7]3 years ago
7 0

Answer:

D. heat energy

Explanation:

This energy is in the form of heat. Evaporation occurs when the liquid is heated. For example, as the sun warms the water in a puddle, the puddle slowly shrinks. Water appears to be vanishing, but it eventually comes through the air as a fluid called a water vapor.

hope this helped!

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Which type of reaction?
polet [3.4K]
condensation polymerization, since a byproduct of the reaction is a single molecule of water (hence condensation of water)

addition polymerization is if you add the two polymers together like blocks and should have no byproducts

esterification is when you combine an organic acid with an alcohol. Since neither of the two polymers look like acids, you can rule this out.

never heard of saponification, Im an mechanical engineer not an organic chemist

3 0
3 years ago
The equation below represents the overall cell reaction for an electrochemical cell that undergoes a spontaneous reaction. Fe(s)
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Its b Fe(s) <span> Fe</span>2+(aq) + 2e– <span><span>       </span>E</span><span> = </span><span>+0.44 V</span>
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PLEASE ANWSER FAST! Gus is performing an experiment on cells. First he places the cells in a container of water and salt. When h
natta225 [31]

Answer:

adding more water to the container

Explanation: because it would cause it to soak up the fluid to created a substance again

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What is the angular momentum of last electron of chromium?
damaskus [11]

Answer:

expected configuration for Cr is

1s2 2s2 2p6 3s2 3p6 4s2 3d4

but in real, it is

1s2 2s2 2p6 3s2 3p6 4s1 3d5

electron from 4s orbital jumps to 3d orbital to get stable configuration.

so the last electron comes in 3d orbital as filling of 3d takes place after filling of 4s orbital.

Hence,quantum numbers for last electron in Cr is :-

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Explanation:

5 0
3 years ago
2. Acidity and basicity of solutions of common substances at 25 ºC: a. Calculate the pH of a sample of lemon juice with [H+ ] =
Lelechka [254]

Answer:

a. The pH of a sample of lemon juice with [H⁺] = 3.8*10⁻⁴ M is 3.4, indicating acidity.

b. The pH of a commonly available window-cleaning solution with [OH⁻] = 1.9*10⁻⁶ M is 8.28,  indicating basicity.

c. The [H⁺] is 1.74*10⁻⁴ M.

d. The [OH⁻] is 1.51*10⁻⁵ M.

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen [H⁺] or hydronium [H₃O⁺] ions present in a solution or substance. Mathematically the pH is the negative logarithm of the molar concentration of the hydrogen or proton ions (H⁺) or hydronium ions (H₃O⁺):

pH= -log₁₀ [H⁺]= -log₁₀ [H₃O⁺] or pH= -log [H⁺]= -log [H₃O⁺]

The pH scale ranges from 0 to 14. Values ​​less than 7 indicate the acidity range and those greater than 7 indicate alkalinity or basicity. Value 7 is considered neutral.

<u><em>Case a</em></u>

You know [H⁺]= 3.8*10⁻⁴ M. Then:

pH= -log (3.8*10⁻⁴)

pH=3.42

<em>The pH of a sample of lemon juice with [H⁺] = 3.8*10⁻⁴ M is 3.4, indicating acidity.</em>

<u><em>Case b</em></u>

Like pH, pOH (or OH potential) is a measure of the basicity or alkalinity of a solution.

The pOH indicates the concentration of hydroxyl ions [OH-] present in a solution:

pOH= -log₁₀ [OH⁻]= -log [OH⁻]

The pOH is related to the pH by the formula:

pH + pOH= 14

In this case you know [OH⁻]=1.9*10⁻⁶ M. Then:

pOH= -log(1.9*10⁻⁶)= 5.72

So pH + 5.72= 14

pH= 14 - 5.72

pH= 8.28

<em>The pH of a commonly available window-cleaning solution with [OH⁻] = 1.9*10⁻⁶ M is 8.28,  indicating basicity.</em>

<u><em>Case c</em></u>

You know pH=3.76. Then:

3.76= -log [H⁺]

-3.76= log [H⁺]

[H⁺]=10^{-3.76}

[H⁺]= 1.74*10⁻⁴ M

<em>The [H⁺] is 1.74*10⁻⁴ M.</em>

<u><em>Case d</em></u>

You know that pH + pOH=14 and pH is 9.18. Then

9.18 + pOH=14

pOH=14 - 9.18

pOH= 4.82

You know pOH= - log [OH⁻]. Then:

4.82= -log [OH⁻]

-4.82= log [OH⁻]

[OH⁻]=10^{-4.82}

[OH⁻]= 1.51*10⁻⁵ M

<em>The [OH⁻] is 1.51*10⁻⁵ M.</em>

3 0
3 years ago
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