<u>Answer:</u> The
for the reaction is 15 kJ.
<u>Explanation:</u>
Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction follows:
![\Delta H^o_{rxn}=?](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%3F)
The intermediate balanced chemical reaction are:
(1)
( × 2)
(2)
![\Delta H_2=-41kJ](https://tex.z-dn.net/?f=%5CDelta%20H_2%3D-41kJ)
(3)
![\Delta H_3=-206kJ](https://tex.z-dn.net/?f=%5CDelta%20H_3%3D-206kJ)
The expression for enthalpy of the reaction follows:
![\Delta H^o_{rxn}=[2\times (-\Delta H_1)]+[1\times \Delta H_2]+[1\times \Delta H_3]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B2%5Ctimes%20%28-%5CDelta%20H_1%29%5D%2B%5B1%5Ctimes%20%5CDelta%20H_2%5D%2B%5B1%5Ctimes%20%5CDelta%20H_3%5D)
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(2\times -(-131))+(1\times (-41))+(1\times (-206))]=15kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20-%28-131%29%29%2B%281%5Ctimes%20%28-41%29%29%2B%281%5Ctimes%20%28-206%29%29%5D%3D15kJ)
Hence, the
for the reaction is 15 kJ.
Then I would guess the answer is D because Na2OH is much more common and stable than Na2O is <span />
Answer:
4.62
so 5
the ratio is 2 na chlorates for 3 O2 so multiply 7 by 2/3
Explanation:
Answer:
12.9 L Kr
General Formulas and Concepts:
<u>Chemistry - Gas Laws</u>
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
0.575 mol Kr
<u>Step 2: Identify Conversions</u>
1 mol= 22.4 L at STP
<u>Step 3: Convert</u>
<u />
= 12.88 L Kr
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
12.88 L Kr ≈ 12.9 L Kr
Answer: Computer chips are very complex, maybe there are things insode that chemists are familiar with. Maybe they can give insight about this.
Explanation: