Question

The Keq for the equilibrium below is 5.4 × 1013 at 480.0 °C. 2NO (g) + O2 (g) 2NO2 (g) What is the value of Keq at this temperature for the following reaction? NO2 (g) NO (g) + 1/2 O2 (g)

Answer 1

Answer: The equilibrium constant for $NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g)$ equation is $1.36\times 10^{-7}$

Explanation:

The given chemical equation follows:

$2NO(g)+O_2(g)\rightleftharpoons 2NO_2(g)$

The value of equilibrium constant for the above equation is $K_{eq}=5.4\times 10^{13}$

Calculating the equilibrium constant for the given equation:

$NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g)$

The value of equilibrium constant for the above equation will be:

$K'_{eq}=\frac{1}{\sqrt{K_{eq}}}\\\\K'_{eq}=\frac{1}{\sqrt{5.4\times 10^{13}}}\\\\K'_{eq}=1.36\times 10^{-7}$

Hence, the equilibrium constant for $NO_2(g)\rightleftharpoons NO(g)+\frac{1}{2}O_2(g)$ equation is $1.36\times 10^{-7}$