Answer:
1. C(s) + O₂(g) ⇄ CO₂(g)
2. ![K=\frac{[CO_{2}]}{[O_{2}]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%7D%7B%5BO_%7B2%7D%5D%7D)
Explanation:
<em>When the oxide of generic metal M is heated at 25.0 °C, a negligible amount of M is produced. MO₂( s ) ⇄ M(s) + O₂(g) ΔG° = 290.2 kJ/mol.</em>
<em />
<em>1. When this reaction is coupled to the conversion of graphite to carbon dioxide, it becomes spontaneous. What is the chemical equation of this coupled process? Show that the reaction is in equilibrium. Include physical states and represent graphite as C(s).</em>
The chemical equation for the coupled reaction is:
C(s) + O₂(g) ⇄ CO₂(g)
<em>2. What is the thermodynamic equilibrium constant for the coupled reaction?</em>
The thermodynamic equilibrium constant (K) is the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.
![K=\frac{[CO_{2}]}{[O_{2}]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%7D%7B%5BO_%7B2%7D%5D%7D)
Answer:
Q = 10.8 KJ
Explanation:
Given data:
Mass of Al= 100g
Initial temperature = 30°C
Final temperature = 150°C
Heat required = ?
Solution:
Specific heat of Al = 0.90 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30°C
ΔT = 120°C
Q = 100g×0.90 J/g.°C× 120°C
Q = 10800 J (10800j×1KJ/1000 j)
Q = 10.8 KJ
U need to do it in cronological order
Answer:
Primary producers
Explanation:
Phytoplankton belong to the <u><em>primary producers</em></u> trophic level. Beings of the other levels gain energy from phytoplankton. Phytoplankton are also capable of transforming inorganic carbon into protoplasm.
Answer:
This is called the pulmonary circulation. From your pulmonic valve, blood travels to the pulmonary artery to tiny capillary vessels in the lungs. Here, oxygen travels from the tiny air sacs in the lungs, through the walls of the capillaries, into the blood.
Explanation: