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2 years ago

What is 76-183+56-1,543 (15 points)

2 answers:

7 0

Use Pemdas
76-183+56-1,543
-107+56-1,543
-51-1,543
−1594

−1594 is your answer.

Hoped I helped!

san4es73 [151]2 years ago

3 0

Answer: First, I would round all numbers (to the nearest tenth).

183 rounds to 180

76 rounds to 80

15 rounds to 20

29 rounds to 30.

Now plug those numbers into the equation.

180/(80-20)+30

Using PEMDAS, I solve the parentheseis first.

80-20=60.

180/60+30

Then, add 60+30.

60+30=90.

you get 180/90.

180/90=2.

Step-by-step explanation:

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Q-The general solution of inequality cos 2 x≤- sin x is

frozen [14]

Answer:

x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I

Step-by-step explanation:

1−2sin2 x≤−sin x ⇒ (2sin x+1)(sin x−1)≥0

sin x≤−1/2 or sin x≥1

−5π/6+2nπ≤x≤−π/6+2nπ or , n ϵ I x=(4n+1)π/2, n ϵ I⇒ -5π6+2nπ≤x≤-π6+2nπ or , n ϵ I x=4n+1π2, n ϵ I (as sin x = 1 is valid only)

In general⇒ In general x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I

3 0

3 years ago

I need help with this worksheet.

marin [14]

Step-by-step explanation:

there are three phases here

in the first phase, the swimmer moved at a constant acceleration, at the second, there was no acceleration since there wasn't any decrease in speed, the third, it's actually deceleration, but it's still constant

6 0

2 years ago

What is the gcf of 120 and 220

yawa3891 [41]

The GCF of 120 and 220 Is 20 :) Its is 20 because both numbers are divisional by 20 Hope this helped and thank u

6 0

3 years ago

How do i write an equation in point-slope form for a horizontal line that passes through(4, –2)??

givi [52]

Answer:

$y = -2$

Step-by-step explanation:

Given

Horizontal Line

$(x_1,y_1) = (4,-2)$

Required

Determine the equation

The equation is calculated using:

$y - y_1 =m(x-x_1)$

Where

$m = slope$

Because the line is a horizontal line, then:

$m = 0$

Substitute 0 for m and values for x1 and y1 in $y - y_1 =m(x-x_1)$

$y - (-2) = 0(x -4)$

$y +2 = 0(x -4)$

$y +2 = 0$

Subtract 2 from both sides

$y +2-2 = 0-2$

$y = -2$

Hence, the equation is: $y = -2$

5 0

2 years ago

Match each pair of points to the equation of the line that is parallel to the line passing through the points.

Luba_88 [7]

Answer:

$B(5,2) \:\: C(7,-5) \:\: \rightarrow y=-3.5x-15$

$D(11,6)\:\: E(5,9)\:\: \rightarrow y=-0.5x-3$

$H(4,4)\:\: I(8,9) \:\: \rightarrow y=1.25x+4$

$L(5,-7)\:\: M(4,-12)\:\: \rightarrow y=5x+9$

Step-by-step explanation:

We need to match the slope of the function with the slope of the lines connecting the two points given. The slope of the lines are as follows:

$B(5,2) \:\: C(7,-5)=\frac{2--5}{5-7} =-3.5$

$D(11,6)\:\: E(5,9)=\frac{6-9}{11-5} =-0.5$

$H(4,4)\:\: I(8,9)=\frac{4-9}{4-8} =1.25$

$L(5,-7)\:\: M(4,-12)=\frac{-7--12}{5-4} =5$

$F(-7,12)\:\: G(3,-8)=\frac{12--8}{-7-3}=-2$

$J(7,2)\:\:K(-9,8) =\frac{2-8}{7--9} =-0.375$

Now,

the slope of the line BC matches with the slope of y=-3.5x-15.

the slope of the line DE matches with the slope of y=-0.5x-3.

the slope of the line HI matches with the slope of y=1.25x+4.

the slope of the line LM matches with the slope of y=5x+9.

and the slopes of the lines FG and JK do not match with any of the functions given.

Thus,

$B(5,2) \:\: C(7,-5) \:\: \rightarrow y=-3.5x-15$

$D(11,6)\:\: E(5,9)\:\: \rightarrow y=-0.5x-3$

$H(4,4)\:\: I(8,9) \:\: \rightarrow y=1.25x+4$

$L(5,-7)\:\: M(4,-12)\:\: \rightarrow y=5x+9$

4 0

2 years ago

Read 2 more answers