Answer:
v2 = 27.3m/s
Explanation:
Assuming forward as positive.
Mass = m1 = 64kg
Let v be the common velocity of the student and the skateboard.
mass of skateboard = m2 = 5.94kg
v = 1.4m/s
Since the skateboard and the student are initially moving together at the same velocity their momentum together is
(m1 + m2)v
Let the final velocity of the student be v1 and the final velocity of the skateboard be v2
v1 = – 1.0m/s (falls backwards that's why the velocity is negative since we are assuming forward as positive)
Then from conservation of momentum, momentum before is equal to momentum after.
(m1 + m2)v = m1v1 + m2v2
m2v2= (m1 + m2)v – m1v1
v2 = ( (m1 + m2)v – m1v1)/m2
v2 = ( (64 + 5.94)×1.4 – 64×(-1.0))/5.94
v2 = ( (64 + 5.94)×1.4 + 64×1.0)/5.94
v2 = 27.3m/s
Answer:
<em>I belive it is 38 degrees</em>
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Explanation:
Earths tilt making the sun go haywire lol XD
v^2-u^2=2 x a x d
25^2-0^2=2 x a x 70
625-0=140 x a
625=140a
a=625/140
a=4.46 m/s^2
im not very sure but i think this is how you do this
Answer: Correct answer is B = 1.776933×
Explanation:
Given :
Moment of inertia I = 8.26×
kg
Mass of planet m = 6.54×
kg
Also, Planet is solid sphere so that, Moment of inertia is I = 
m
=0.4m
Where R is radius of planet
Putting into calculation
We get,
I = m
8.26× = 0.4×6.54××
8.26×
= 2.616
3.15749235× =
R = 1.776933×
Thus, Correct answer is B = 1.776933×
