Answer:
-4
Step-by-step explanation:
In order to get from point -1, 8, to point 2, -4, you would have to go down 12 and right 3, which would be 12/-3, which would simplify to -4
Answer:

Step-by-step explanation:

Subtract x from both sides.


Square both sides.


Subtract x²-6x+9 from both sides.


Factor left side of the equation.

Set factors equal to 0.


Check if the solutions are extraneous or not.
Plug x as 2.

x = 2 works in the equation.
Plug x as 6.

x = 6 does not work in the equation.
9a
This is because 3^2 is equal to 9 and <span>√a^2 is equal to a. </span>
I think that this is right, but I assumed that the ceiling has the same dimensions as the wall you would need 4 gallons for 2 coats.
Work:
20x8= 160 (square feet for 1 wall)
160x5=800 (i assumed there are 4 walls and 1 ceiling)
800x2=1600 (you need 2 coats)
1600/400=4 (each gallon includes 400 square feet)