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3 years ago

PLZ HELP WITH ALGEBRA 1/3 (45- 18/7) Please put into simplest form

Mathematics

1 answer:

Temka [501]3 years ago

6 0

Here is the answer- 297. I hope this helps! I solved this by changing the fractions so that they had the same denominators.

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a cow is tied to a tree with a 15 ft long rope. Determine the circumference and area in which the cow can graze.

Nookie1986 [14]

Check picture below, radius = r = 15, thus

8 0

3 years ago

Factor x^2-10x+25,please show work

Papessa [141]

This is relatively easy because that 25 is a perfect square, whose (square) roots are 5 and -5. x^2-10x+25 = (x - 5)(x - 5). Note how (-5)(-5) = +25, and how -5x - 5x = -10x.

The roots are { (x-5), (x-5) }.

5 0

3 years ago

A particular fruit's weights are normally distributed, with a mean of 405 grams and a standard deviation of 19 grams. If a fruit

cluponka [151]

Answer:

413.126

Step-by-step explanation:

Given a normal distribution :

Mean (m) = 405

Standard deviation (s) = 19

Weight of fruit will be greater than how many grams (x) if picked 17% of the time:

P(Z > x) = 0.17 ;

The Zscore for P(Z > x) = 0.17 equals 0.954 (Z probability calculator)

Zscore = (x - m) / s

0.954 = (x - 405) / 19

0.954 * 19 = x - 405

18.126 = x - 405

x = 18.126 + 405

x = 423.126

Weight will be greater than 423.126

8 0

3 years ago

The number of people , d, in thousands applying for medical benefits per week in a particular city can be modules by the equatio

Mekhanik [1.2K]

Answer:

<h2>4773 peoples.</h2>

Step-by-step explanation:

Given the number of people d, in thousands applying for medical benefits per week in a particular city c modeled by the equation d(t)=2.5 sin(0.76t+0.3)+3.8 where t is the time in years, the maximum number of people tat will apply will occur at d(t)/dt = 0

Differentiating the function given with respect to t, we will have;

$d(t)=2.5 sin(0.76t+0.3)+3.8$

First we need to know that differential of any constant is zero.

$Using\ chain\ rule\\\frac{d(t)}{dt} = 2.5cos(0.76t+0.3) * 0.76 + 0\\ \\\frac{d(t)}{dt} = 1.9cos(0.76t+0.3)$

If $\frac{d(t)}{dt} =0$ then;

$1.9cos(0.76t+0.3) = 0\\\\cos(0.76t+0.3) = 0\\\\0.76t+0.3 = cos^{-1} 0\\\\0.76+3t = 90\\\\3t = 90-0.76\\3t = 89.24\\\\t = 89.24/3\\\\t = 29.75years$

To know the maximum number of people in thousands that apply for benefits per year in the city, we wil substitute the value of t = 29.75 into the modeled equation

$d(t)=2.5 sin(0.76t+0.3)+3.8\\d(29.75) = 2.5 sin(0.76(29.75)+0.3)+3.8\\d(29.75) = 2.5 sin(22.61+0.3)+3.8\\\\d(29.75) = 2.5 sin(22.91)+3.8\\\\d(29.75) = 0.9732+3.8\\d(29.75) = 4.7732\\\\$

Since d is in thousands, the maximum number of people in thousands will be 4.7732*1000 = 4773.2 which is approximately 4773 peoples.

3 0

3 years ago

Select the correct answer.

g100num [7]

The correct answer is the letter B

7 0

3 years ago