Question 3 Unsaved

G (where g=9.8 m/s2). If an object’s mass is m=10. kg, what is its weight?

Semenov [28]

$F_{w} =m*g \\ F_{w} =10*9.8=98N$

7 0

4 years ago

The satellite s travels around the earth in a circular path with a constant speed of 20 mm>h. If the acceleration is 2.5 m&gt

Zanzabum

<u>Answer:</u>

The altitude of planet = 5989.198 km

<u>Explanation:</u>

We know that centripetal acceleration, $a = v^2/r$ , where v is the velocity and r is the radius. In this case both acceleration and velocity is given, so we can find radius of satellite.

v = $20 Mm/hr = 20*10^6/3600 = 5555.56 m/s$

a = $2.5 m/s^2$

So, $2.5 = 5555.56^2/r\\ \\ r = 12345698.77 m = 12345.698km$

We have diameter of earth = 12713 km

Radius of earth = 12713/2 = 6356.5 km

The altitude of planet = Radius of planet - radius of earth

= 12345.698 - 6356.5

= 5989.198 km

8 0

3 years ago

A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches in 9.00 seconds? Given: g

Hitman42 [59]

The distance traveled while accelerating from rest is

   D = 1/2 a t² .

For this problem, we shall totally ignore air resistance.
We do so completely without any reservation or guilt,
because we know that there is no air on the moon.

   D = (1/2) · (1.6 m/s²) · (9 sec)²

   = (0.8 m/s²) · (81 s²)

   = (0.8 · 81) m

   = 64.8 meters .

(That's about 213 feet ! The astronaut must have dropped the feather
from his spacecraft while he was aloft ... either just before touchdown
or just after liftoff.)

3 0

3 years ago

Read 2 more answers

4. What information does the atomic number of an element give us?

bulgar [2K]

Answer: It gives us the identity of the element as well as the number of protons.

Explanation:

Because the number of protons is specific for each element, we can determine what element we are looking at just by the atomic number. For example the element with the atomic number of 1 is Hydrogen, atomic number of 2 is Helium, atomic number of 3 is Lithium and so forth.

5 0

4 years ago

A truck with a mass of 4285 kg is moving at 9. 35 m/s. it crashes into the rear end of a larger truck with a mass of 5495 kg mov

iogann1982 [59]

(a) The final velocity if the trucks lock together after the collision is 7.66 m/s.

(b) The decrease in the kinetic energy after the collision is 11,165.1 J.

<h3>Conservation of linear momentum</h3>

The final velocity of the two truck system after the collision is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

4285(9.35) + 5495(6.35) = v(4285 + 5495)

74,958 = 9,780v

v = 74,958/9780

v = 7.66 m/s

<h3>Initial kinetic energy of the trucks</h3>

K.E = ¹/₂mv²

K.Ei = ¹/₂(4285)(9.35)² + ¹/₂(5495)(6.35)²

K.Ei = 298,088.78 J

<h3>Final kinetic energy of the trucks</h3>

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(4285 + 5495)(7.66)²

K.Ef = 286,923.68 J

<h3>Change in kinetic energy</h3>

ΔK.E = K.Ef - K.Ei

ΔK.E = 286,923.68 J - 298,088.78 J

ΔK.E = - 11,165.1 J

Learn more about linear momentum here: brainly.com/question/7538238

4 0

2 years ago