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Brrunno [24]
3 years ago
15

The satellite s travels around the earth in a circular path with a constant speed of 20 mm>h. If the acceleration is 2.5 m&gt

;s2, determine the altitude h. Assume the earth's diameter to be 12 713 km.
Physics
1 answer:
Zanzabum3 years ago
8 0

<u>Answer:</u>

The altitude of planet = 5989.198 km

<u>Explanation:</u>

    We know that centripetal acceleration, a = v^2/r, where v is the velocity and r is the radius. In this case both acceleration and velocity is given, so we can find radius of satellite.

    v = 20 Mm/hr = 20*10^6/3600 = 5555.56 m/s

    a = 2.5 m/s^2

 So,  2.5 = 5555.56^2/r\\ \\ r = 12345698.77 m = 12345.698km

 We have diameter of earth = 12713 km

        Radius of earth = 12713/2 = 6356.5 km

   The altitude of planet = Radius of planet - radius of earth

                                         = 12345.698 - 6356.5

                                         = 5989.198 km

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