Answer:
Explanation:
Given the following ;
- TA = 77°C and TB = 62°C at x1, KA = 180w/mk
- Tb = 100°C and T[infinity] = 25°C
The two rods could be approximated as a fins of infinite length.
- TA = 77 0C, θA = (TA - T∞) = 77 - 25 = 52 0C
- TB = 62 0C , θB = (TB - T∞) = 62 - 25 = 37 0C
- Tb = 100 0C , θb = (Tb - T∞) = (100 - 25) = 75 0C
The temperature distribution for the infinite fins are given by ;
- θA/θb= e-√(hp/A.kA) x1 ....................(1)
- θB/θb = e-√(hp/A.kB) x1.......................(2)
Taking natural log on both sides we get,
- In(θA/θb) = -√(hp/A.kA) x1 ...................(3)
- In(θB/θb) = -√(hp/A.kB) x1 .....................(4)
- [ In(θA/θb) / In(θB/θb)] = √(KB/KA)
- [ In(52/75) / In(37/75)] = √(KB/180)
- KB = 48.36W/m. K, Hence The thermal conductivity of the second material is KB = 48.36 W/m.K
Answer:
The mass of the banana is m and it is at height h.
Applying the Law of Conservation of Energy
Total Energy before fall = Total Energy after fall
=
Here, total energy is the sum of kinetic energy and potential energy
+
=
+
(a)
When banana is at height h, it has
= 0 and
= mgh
and when it reaches the river, it has
= 1/2m
and
= 0
Putting the values in equation (a)
0 + mgh = 1/2m
+ 0
mgh = 1/2m
<em>cutting 'm' from both sides</em>
<em> </em>gh = 1/2
v = 
Hence, the velocity of banana before hitting the water is
v = 
Answer:

Explanation:
= Refractive index of glass = 1.5
= Speed of light in vacuum = 
Refractive index is given by

The speed of light in the glass is
.