In a physics lab experiment, a spring clamped to the table shoots a 22g ball horizontally. When the spring is compressed 21cm ,
1 answer:
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We will apply the concepts related to Newton's second law. At the same time we will convert everything to the system of international units.
The values of the velocities are,
We know that the acceleration is equivalent to the change of the speed in a certain time therefore
Now applying the Newton's second law we have,
Therefore the approximate magnitude is 8516.36N
Answer:
0.49 m/s
Explanation:
The law of conservation of linear momentum states that the sum of momentum in a system before and after collision are same. Momentum is a product of mass and velocity of an object hence in this case
Where m represent mass, u and v represent the initial and final velocities respectively, subscripts c and 8 represent cue ball and number 8 ball respectively.
Since number 8 ball is initially at rest, its initial velocity is zero. Replacing mass of cue ball with 170 g while mass of number 8 ball with 160g, then taking final velocity of cue ball as 0.2 m/s and final velocity of 8 ball as 0.3 m/s then we get