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Verizon [17]
1 year ago
5

a ball is shot from the ground straight up into the air with initial velocity of 50 50 ft/sec. assuming that the air resistance

can be ignored, how high does it go?
Physics
1 answer:
Anna [14]1 year ago
3 0

The height attained by the ball is 11.86m

a ball is shot from the ground straight up into the air its initial and final velocity is

initial velocity, u = 50 ft/s = 50×0.305  = 15.25m/s

final velocity ,v = 0 m/s

gravity =-9.8 m/s²

( negative sign shows acceleration in opposite direction)

height =?

using the newton motion of equation

v² = u² + 2as

where

a= acceleration due to gravity(g)

s = height

v² = u² + 2gs

(0)² = (15.25)² + 2×(-9.8)×s

0  = (15.25)² -  19.6 × s

s= - (15.25)²/ 19.6

s = 11.86m

after ignoring the air resistance the maximum height of the ball is 11.86m

To learn more about motion under gravity -

brainly.com/question/27962354

#SPJ4

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Answer:

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Explanation:

The computation of the mass of the car is shown below:

As we know that

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Provided that:

Fc = 34.652 kN = 34652 N

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So,

m = 34652 × 24.98 ÷ 15.67^2

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7 0
3 years ago
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6 0
3 years ago
If a boulder has a weight of 675,000 N what is it’s mass
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Mass = (675,000 N) / (3.71 m/s²)

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