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-Dominant- [34]
4 years ago
13

Sam was paid 260 for working 40 hours

Mathematics
2 answers:
iren2701 [21]4 years ago
7 0
260 ... 40 hours
x = ? ... 1 hour

If you would like to know how much was Sam paid for working one hour, you can calculate this using the following steps:

260 * 1 = x * 40
260 = x * 40     /40
x = 260 / 40
x = 6.5

Result: Sam was paid 6.5 for working 1 hour.
wolverine [178]4 years ago
4 0
Divide 260 by 40 hours: 260÷40=6.5. Therefore, Sam was paid 6.5 for 1 hour.
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t hits the square dartboard shown below at a random point. Find the probability that the dart lands in the shaded circular regio
masha68 [24]

Given:

Required:

To find the probability that the dart land will be in the shaded region.

Explanation:

Area of the circle is given by the formula:

A=\pi r^2

Where r = radius

Thus the area of the circular region

\begin{gathered} =(3.14)\times(2)^2 \\ =3.14\times4 \\ =12.56\text{ square in.} \end{gathered}

The area of the square is given by the formula:

=(side)^2

Thus the area of the given square

\begin{gathered} =(6)^2 \\ =36\text{ square in.} \end{gathered}

The probability of an event is given by the formula:

P=\frac{number\text{ of possible outcomes}}{Total\text{ number of outcomes}}

The probability that the dart land will be in the shaded region

=\frac{Area\text{ of the shaded region}}{Area\text{ of the square}}

Thus probability

\begin{gathered} P=\frac{12.56}{36} \\ P=0.3488 \\ P=0.349 \end{gathered}

Final answer:

Thus the probability that the dart land will be in the shaded region is 0.349.

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Find the midpoint of the segment with the following end points (10,5) and (6,9)
Taya2010 [7]

Answer:

The mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)

Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

  • (10,5)
  • (6,9)

Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here:

\left(x_1,\:y_1\right)=\left(10,\:5\right),\:\left(x_2,\:y_2\right)=\left(6,\:9\right)

Thus,

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

\left(x,\:y\right)=\left(8,\:7\right)

Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)
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Ierofanga [76]

Answer: 8.4

Step-by-step explanation:

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3 years ago
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