Let X = the large #
Y = the small #
We have 2 unknowns, therefore we need 2 equations to solve for them:
X + Y = 61
X = 3Y - 7
Using the substitution method we get:
X + Y = 61 original equation
(3Y - 7) + Y = 61 substituting for X
4Y - 7 = 61 combine like terms
4Y - 7 + 7 = 61 + 7 add 7 to both sides
4Y = 68 simplify
4Y/4 = 68/4 divide both sides by 4
Y = 17 solve for Y
X + Y = 61 original equation
X + 17 = 61 replace Y with 17
X + 17 - 17 = 61 - 17 subtract 17 from both sides
X = 44 solve for X
Check your answer:
X + Y = 61 X = 3Y - 7
44 + 17 = 61 44 = 3(17) - 7
61 = 61 check! 44 = 51 - 7
44 = 44 check!
Therefore, the larger #(X) = 44 and the smaller #(Y)= 17.
Answer:
a = 0.4 and b=1.6
Step-by-step explanation:
Both expressions are simply divided
(2x + 8y = 60) ÷ (ax + by = 12)
60÷12 = 5, Hence coefficient of x and y in the bigger equation is divided by 5 to find a and b
2/5 = 0.4 = a
8/5= 1.6 = b
Answer:
hiiii....
Step-by-step explanation:
b)2and4 only
25 is the answer to your question
Answer:
∠a = <u>51°</u>
∠b = <u>48°</u>
∠c = <u>70°</u>
Step-by-step explanation:
∠c = 180° - 110° = <u>70°</u> (Angles on a straight line add up to 180°)
∠ADB = 180° - (110° + 19°) = <u>51°</u> (Angles on a triangle add up to 180°)
∴ ∠a = <u>51°</u> (Alternate angles are equal)
∠A = 180° - (51° + 62°) = <u>67°</u> (Angles on a triangle add up to 180°)
∠CAB = 67° - 19° = <u>48°</u>
∴ ∠b = <u>48°</u> (Alternate angles are equal)
