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kondaur [170]
3 years ago
10

What equation in the blast furnace extraction of iron is not a redox reaction?

Chemistry
1 answer:
Misha Larkins [42]3 years ago
8 0

The decomposition of limestone CaCO3 > CaO + CO2

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Select the correct answer.
spayn [35]

it would be B because warm humid air+cool land=fog

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3 years ago
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Summarize the weather conditions related to a cold front. Remember to include all data collected on cold fronts in this activity
svp [43]

Answer: Many fronts cause weather events such as rain, thunderstorms, gusty winds and  A weather front is a transition zone between two different air masses at the  Lifted warm air ahead of the front produces cumulus or cumulonimbus clouds

Explanation:

Hope this was helpful

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3 years ago
What is similar about the atomic structure of the copper isotopes?
jasenka [17]
All copper atoms have atomic number 29: all their nuclei contain 29 protons. But they also contain uncharged particles called neutrons. ... The two different kinds of atom are called isotopes of copper. The neutron has a mass very similar to that of the proton, so the two isotopes differ in mass.
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3 years ago
I need help with this please
jarptica [38.1K]

Answer: the place that i put the letters is how it should look also 75% of your peas are green

Explanation:

3 0
3 years ago
Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse
amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given  by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

6 0
3 years ago
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