None of the given statements are completely true.
<u>Explanation</u>:
Family or groups in "periodic table" are 18 in number which represents column in table. As we go down in a family or group in the "periodic table"-the atom size become bigger and bigger. Non-Metals are less reactive which mostly lie in p-block. "Metals" are ""ore reactive" in "s-block". The atom’s valence electrons remain same for example when we go down in alkali metals in s-block the valence electron is one only and in alkaline earth metals its two only.
Answer:
34.05dm^3 of nitrogen gas
Explanation:
First things first, we need to find the number of moles of Sodium azide. We can do that by using the formula m=nM, mass = no. moles x Molar Mass
Rearrange to solve for no. moles and substituting in the known values and we have:
n = m/M
no. moles = 130.0g / (2x(22.99+3x14.01))
no. moles = 130.0/130.0 (4.s.f.)
no. moles = 1
Now we can use the ratio given in the equation to find the number of moles of Nitrogen that will be made:
1 x 3/2 = 1.5 moles of Nitrogen
Now we use the constant that 1 mole of any gas will always have a volume of 22.7dm^3 at STP.
1.5 x 22.7 = 34.05dm^3 of nitrogen gas.
Hope this helped!
"40 million years" ago <span>did the two species share a common ancestor if the molecules found in these two species differ by a total of eight mutations. The correct option among all the options that are given in the question is the fourth option or the last option. I hope that this is the answer that has come to your help.</span>
Answer:
The answer to your question is 6.54 g of H₂O
Explanation:
Data
mass of water = ?
mass of carbon dioxide = 16 g
Balanced chemical reaction
H₂CO₃ ⇒ H₂O + CO₂
Process
1.- Calculate the molar mass of the products
H₂O = (1 x 2) + (1 x 16) = 2 + 16 = 18 g
CO₂ = (1 x 12) + (16 x 2) = 12 + 32 = 44 g
2.- Use proportions and cross multiplication to solve this problem.
18 g of H₂O -------------------- 44 g of CO₂
x -------------------- 16 g of CO₂
x = (16 x 18) / 44
x = 288/44
x = 6.54 g of H₂O
Explanation:
Molar mass
The mass present in one mole of a specific species .
The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .
(a) )hydrogen fluoride, HF
Since ,
Molar mass of of the atoms are -
Hydrogen , H = 1 g/mol
Fluorine, F = 19 g/mol.
Molar mass of HF = ( 1 g/mol ) + ( 19 g/mol ) = 20 g/mol.
(b) ammonia, NH₃
Molar mass of of the atoms are -
nitrogen, N = 14 g/mol
and Hydrogen , H = 1 g/mol
Molar mass of NH₃ = 14 + ( 3 x 1 ) g/mol = 17 g/mol.
(c) nitric acid , HNO₃
Molar mass of of the atoms are -
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
nitrogen, N = 14 g/mol
Molar mass of HNO₃ = (1 g/mol ) + ( 14 g /mol) + ( 3 x 16 ) = 63 g/mol.
(d)Silver sulfate, Ag₂SO₄
Molar mass of of the atoms are -
silver, Ag = 108 g/mol
sulfur, S = 32 g/mol.
oxygen , O = 16 g/mol.
molar mass of Ag₂SO₄ = ( 2 x 108 g/mol ) + ( 32 g /mol )+ (4 x16 g/mol )
=312 g/mol.
(e )boric acid , B(OH)₃
Molar mass of of the atoms are -
boron , B = 11 g/mol
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
Molar mass of B(OH)₃ = ( 11 ) + ( 3x16 ) + ( 3 x 1 ) = 62 g/mol.