Answer:
k
Explanation:
electron affinity (EA) depends on various factors like effective nuclear charge (enc) , size of the atom, ellipticity of sub-shell (ep) , nature of configuration.
more is the enc more will be the EA
more is the size less will be the EA
more valance shell ellipticity (closer to the nuclei) more will the EA ( all given element posses P orbital in the valance shell)
Answer:
The new volume is 2415 mL
Explanation:
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases.
Boyle's law says that the volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure and is expressed mathematically as:
P * V = k
Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. This can be expressed mathematically in the following way:

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

Having two different states, an initial state and an final state, it is true:

In this case:
- P1= 0.9 atm
- V1=4,600 mL= 4.6 L (being 1 L=1,000 mL)
- T1= 195 °C= 468 °K (being 0°C=273°K)
The final state 2 is in STP conditions:
- P2= 1 atm
- V2= ?
- T2= 0°C= 273 °K
Replacing:

Solving:

V2= 2.415 L =2,415 mL
<u><em>The new volume is 2415 mL</em></u>
We are given an equation 2Mg+O2-> 2MgO and a starting chemical Mg of about 212 g. In order to solve for the amount of O2 needed, we need the molecular weight of Mg and O2.
Molecular weight:
Mg=24.305 g/mol
O2=16(2)=32 g/mol
Note that for every 1 mol of O2, the amount of Mg must be 2 mol.
So,
g O2 = 212 g Mg x1mo Mgl/24.305 g Mg x1mol O2 /2 mol Mg x 32 g O2/mol O2
gO2=139.56 g
Therefore, 139.56 g of O2 is needed for every 212 g Mg.