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3 years ago

The South Pole has warm summers. True False

Chemistry

1 answer:

agasfer [191]3 years ago

7 0

Answer:False

Explanation:

Kinda of a opinionated question, but unless you call -12 C warm then the answer is False

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(BRAINLIEST) Coal burning plants produce less air pollution than nuclear power plants

Alecsey [184]

Answer:

the answer of this question is true

7 0

3 years ago

4. Ammonium nitrate (NH4NO3) fertilizer decomposes explosively into gaseous nitrogen, oxygen, and water, resulting in huge therm

AURORKA [14]

Answer:

280 g

Explanation:

Let's consider the decomposition of ammonium nitrate.

NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)

We can establish the following relations:

The molar mass of NH₄NO₃ is 80.04 g/mol.
The molar ratio of NH₄NO₃ to N₂ is 1:1.
The molar mass of N₂ is 28.01 g/mol.

The mass of N₂ produced when 800 g of NH₄NO₃ react is:

$800gNH_{4}NO_{3}.\frac{1molNH_{4}NO_{3}}{80.04gNH_{4}NO_{3}} .\frac{1molN_{2}}{1molNH_{4}NO_{3}} .\frac{28.01gN_{2}}{1molN_{2}} =280gN_{2}$

6 0

3 years ago

The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i

antoniya [11.8K]

Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

$Q=mc\Delta T +m\Delta H_{fusion}$

$\Delta T=(T_{final}-T_{initial})=(1064^oC-32^oC)=1032^oC$

c = specific heat capacity of gold = 0.1291 $joules/gram^oC$

m = mass of gold =15.71 g

$Q=15.71 g\times 0.1291 joules/gram^oC (1032^oC) +15.71 g\times 63.5 Joules/gram$

Heat gained by gold = $2093.0621 Joules + 997.585 Joules$

=3090.6471 joules

6 0

3 years ago

How many moles of I(iodine)2 are there in a 500.0g bottle? Please include significant figures

dolphi86 [110]

Answer:

Number of moles = 1.97 mol

Explanation:

Given data;

Number of moles of I₂ = ?

Mass = 500.0 g

Solution:

Number of moles = mass/ molar mass

Molar mass of I₂ = 253.8 g/mol

Number of moles = 500 g / 253.8 g/mol

Number of moles = 1.97 mol

4 0

3 years ago

How much energy is required to boil 65 grams of 100°C water<br> And then heat the steam to 150°C?

Artyom0805 [142]

Answer:

13598 J

Explanation:

Q = m × c × ∆T

Where;

Q = amount of energy (J)

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

m = 65g, specific heat capacity of water = 4.184J/g°C, initial temperature= 100°C, final temperature = 150°C

Q = 65 × 4.184 × (150 - 100)

Q = 271.96 × 50

Q = 13598 J

Hence, 13598 J of energy is required to boil 65 grams of 100°C water and then heat the steam to 150°C.

8 0

3 years ago