Answer:
0.4550
Explanation:
In this example, R allele is dominant, so individuals RR and Rr can roll their tongues. If in a population of 1000 gorillas, there are 575 gorillas who can roll their tongues, they will be RR and Rr.
In this case, there is Hardy Weinberg Equilibrium, so the following will be true:
Where:
frequency of RR
frequency of Rr
frequency of rr
The question is what is the frequency of heterozygotes, or, what is the value of 2pq.
We know that RR+Rr is 575 individuals in a population of 1000, or 0.575.
In other words:
So, it is possible to find :
Now, there are two alleles in the population, so the following will be true:
It is possible to find q (the frequency of allele r) and p (the frequency of allele p):
Therefore:
Now, the frequency of heterozygotes or 2pq is:
A planet in our solar system is like the earth it is stable to live on but anything can happen while you are on it but and a dwarf planet it is not for everyday life so humans can not live on a dwarf planet like they could on one in the solar system
Primary, so the first option, or option A
It’s 1 widows peak 3 straight hairline