The membrane bound organelle you refer to is the Lysosome. The lysosome fuses with a vacuole where it digest the contents.
The answer is C. Chromsomes make up part of the DNA and carry the information needed to code for the DNA's proteins.
Answer:
0.483
Explanation:
The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.
Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1
If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41
The frequency of heterozygous genotype in the population= 2pq
p= frequency of the dominant allele
q= frequency of the recessive allele
So, 2pq= 2 x 0.59 x 0.41 = 0.483
Answer:
The correct answer would be C. The protein synthesized will contain many erroneous amino acids since the loss of one base will shift the reading of the encoded base sequence.
Deletion mutation that does not occur in the multiple of three bases can results in frame-shift mutation.
It changes the reading frame of nucleotide in DNA. Thus, the reading frame of codons in mRNA would also change.
Consequently, the sequence of amino acids in a polypeptide chain would change or alter. Thus, a protein would contain many erroneous amino acids.
An example of the same is shown below in the image.
Answer:
Box 1: AA
Box 2: Aa
Box 3: AA
Explanation:
In order to figure out the pedigree, you first have to do a punnet square- kind of like cross-multiplying. EX: For the first box: Aa x AA
For box one, we know that it is Aa, and not AA, because box 2 has to be AA.
We know that because Aa X Aa would give us some "aa" offspring which we do not see in the last generation (see 2nd pic). The only way to get no "aa" offspring is to have an AA X Aa cross.