I can answer it but is the “S” supposed to be an integral?
Answer:
0.0244 (2.44%)
Step-by-step explanation:
defining the event T= the chips passes the tests , then
P(T)= probability that the chip is not defective * probability that it passes the test given that is not defective + probability that the chip is defective * probability that it passes the test given that is defective = 0.80 * 1 + 0.20 * 0.10 = 0.82
for conditional probability we can use the theorem of Bayes. If we define the event D=the chip was defective , then
P(D/T)=P(D∩T)/P(T) = 0.20 * 0.10/0.82= 0.0244 (2.44%)
where
P(D∩T)=probability that the chip is defective and passes the test
P(D/T)=probability that the chip is defective given that it passes the test
I think it’s b to be honest with you
Answer:
No, because there is just as high of a possibility that the other is biased too.
Answer:
0
Step-by-step explanation:
First what you want to do is add together the common numbers
So, take all of the X's and add them together
(-11, 8, and 3)
-11x + 8x + 3x
-3x + 3x
0
So that all evens out
Now just find the other values
(4 and -4)
4 - 4
0
This equation equals 0
Hope this helps!!!
-Unicorns110504
*Please mark brainliest*