First, find the slope (m) = =
=
=
Now plug in ONE of the points and the slope into the point-slope equation:
y - y₁ = m(x - x₁); where (x₁, y₁) is the chosen point.
y - 5 = (x - 1) (I used (1,5) as the chosen point)
3(y - 5) = x - 1
3y - 15 = x - 1
3y -14 = x
-14 = x - 3y → x - 3y = -14
Answer: x - 3y = -14
Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) }
This area is equal to 125 as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒ - 18 a +80 -125 =0
⇒ - 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a 4.
Thus the required answer is 15 cm.