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Leto [7]
3 years ago
6

For which process is ΔS negative? Group of answer choices A. grinding a large crystal of KCl to powder B. raising the temperatur

e of 100 g Cu from 275 K to 295 K C. compressing 1 mol Ne at constant temperature from 1.5 L to 0.5 D. mixing 5 mL ethanol with 25 mL water E. evaporation of 1 mol of CCl4(l)
Chemistry
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

C.

Explanation:

The entropy (S) is the measure of the randomness of a system, and ΔS = Sfinal - Sinitial. As higher is the disorder of the system, as higher is the entropy.

A. When KCl is fractionated in power, there'll be more portions of it, so, the disorder must be higher, then ΔS is positive.

B. As higher is the temperature, higher is the kinetic energy of the system, and because of that, the disorder is also higher, so ΔS is positive.

C. The decrease in the volume (compression) decreases the distance between the molecules, so the system will be more organized, then ΔS is negative.

D. The volume before the mixing will be higher, and the ethanol will dissociate, so it will be more particles, the disorder will increase, and ΔS is positive.

E. Sgas > Sliquid > Ssolid because of the disorder of the molecules, then ΔS is positive.

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Give the structure of the product obtained when cyclopropene loses a proton. Will the product be aromatic or not?
astra-53 [7]

Answer:

not aromatic

Explanation:

Cyclopropene -

as the compound is is made to lose a proton , and gains a negative charge on its ring ,

Now, The ring can become aromatic or anti - aromatic depending on the number of π electrobns ,

According to Huckel 's rule ,

The cyclic compounds with ( 4n+2 ) π electrons , where , n = 0, 1, 2, 3 ... , are considered to be aromatic in nature ,

And the cyclic compounds with ( 4n ) π electrons , where , n = 1, 2, 3 ... , are considered to be anti - aromatic in nature.

Now, for the cyclopropene structure , the number of π electron are equal to 4 , 2 from the double bond and 2 from the negative charge .

Therefore , the compound becomes not aromatic or anti - aromatic .

3 0
3 years ago
If ammonia were formed from dalton's simplest formula of one atom of each element, what would he have concluded about the relati
baherus [9]
He would have concluded that the order of operations would be different. This therefore would affect the periodic table's order. 
8 0
3 years ago
Which scientist arranged the elements in order of increasing atomic number, rather than increasing atomic mass?
pentagon [3]

Answer:

Henry Moseley

Explanation:

Dmitry Mendeleef and Lothar Meyer proposed a periodic table based on the atomic mass.

They stated a periodic law expressed as "chemical properties of elements are a periodic function of their atomic weights".

But, Henry Moseley in 1900s re-stated periodic law by changing the basis of the law from atomic weight to atomic number.

The present periodic law is stated as "the properties of elements are a periodic function of their atomic number".

6 0
2 years ago
A mixture of gases A2 and B2 are introduced to a slender metal cylinder that has one end closed and the other fitted with a pist
REY [17]

Answer:

q < 0, w > 0, the sign of ΔE cannot be determined from the information given

Explanation:

Determination of sign of q

Temperature of the water bath before the reaction = 25 °C

Temperature of the water bath after the completion of the reaction = 28 °C

After the completion of the reaction, temperature of the water bath is increased that means heat is released during the reaction and flows out of the system.

If heat is absorbed by the system, then q is indicated by positive sign and if heat is released by the system, then q is indicated by negative sign.

As in the given case, heat is released by the system, so sign of q is negative, or q < 0

Determination of sign of w

After the completion of the reaction, piston moved downward, that means volume of the system decreases or compression occur. During the compression, work is done on the system.

if work is done on the system, sign of w is positive.

If work is done by the system, sign of w is negative.

In the given case, work is done on the system, therefore sign of w is positive, or w > 0

Determination of sign of ΔE

Relationship between ΔE, q and w is given by first law of thermodynamics:

ΔE = q + w

In this case, q is positive and w is negative, so the sign of ΔE depends of magnitude of q and w. As magnitude of w and q cannot be determined in this case, thus, the given information is insufficient for the determination of sign of ΔE.

So, among the given option, option c is correct.

q < 0, w > 0, the sign of ΔE cannot be determined from the information given

3 0
3 years ago
7. Calculate moles of H2 needed to form 2.25 moles HCl in the reaction H2 + Cl2==&gt;2HCl
mart [117]

Answer:

1.125 moles

Explanation:

2mole of HCl produced 1mole of H2

2.25moles of HCl will produce x moles

cross multiply

2x=™1×2.25

x= 2.25÷2

x=1.125mole

8 0
3 years ago
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