All categories

3 years ago

Which of the following is an example of a molecule?

Chemistry

1 answer:

xxMikexx [17]3 years ago

5 0

O2 is an example of a molecule

You might be interested in

How many moles are in 3.4 x 10^23 atoms of O2?

Tamiku [17]

Answer:

5.00 moles..hope it helps

7 0

3 years ago

At some temperature, the reaction: 3 clo- ? clo3- 2 cl- has an equilibrium constant kc = 3.2 x 103. if the components of this re

Scilla [17]

Gagagagaagagry rftdadadad

4 0

3 years ago

5.If 30mL of 0.5M NaOH(aq) was used to neutralize 10mL of HCl(aq), what is the concentration of the acid? Show work.

Zolol [24]

Answer:

0.15M

Explanation:

NaOH + HCl -->NaCl + H2O

moles of NaOH reacted with HCl

(0.5 × 30)/1000 = 1.5 × 10^ -3

so the moles of HCl reacted with NaOH

1.5 × 10^ -3

concentration of HCl = ( 1.5 × 10^ -3)/10 ×1000

7 0

3 years ago

Through 100 ml of a one-molar sodium hydroxide solution, 896 ml (n.a.) of carbon dioxide was passed gas. Determine the mass solu

Semmy [17]

Through 100 ml of a one-molar sodium hydroxide solution, 896 ml (n.a.) of carbon dioxide was passed gas. Determine the mass solution of salt in the resulting solution. Density of a one-molar alkali solution, take equal to 1.04 g / ml.

5 0

3 years ago

Polonium is a rare element with 33 radioisotopes. The most common one, 210Po, has 82 protons and 128 neutrons. When 210Po decays

Varvara68 [4.7K]

Answer:

$\boxed{_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} + \,_{2}^{4}\text{He}}$

Explanation:

The unbalanced nuclear equation is

$_{84}^{210}\text{Po} \longrightarrow \, ? + \,_{2}^{4}\text{He}$

It is convenient to replace the question mark by an atomic symbol, $_{x}^{y}\text{Z}$ , where x = the atomic number, y = the mass number, and Z = the symbol of the element .

Then your equation becomes

$_{84}^{210}\text{Po} \longrightarrow \, _{x}^{y}\text{Z} + \,_{2}^{4}\text{He}$

The main point to remember in balancing nuclear equations is that **the sums of the superscripts and the subscripts must be the same on each side of the equation**.

Then

84 = x + 2, so x = 84 - 2 = 82

210 = y + 4, so y = 206

Element 82 is lead, so the nuclear equation becomes

$\boxed{_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} + \,_{2}^{4}\text{He}}$

4 0

3 years ago