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Vlad [161]
2 years ago
12

I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2CuCl2+4KI⟶2CuI+4KCl+I2. What volume

of I2 gas is produced at STP?
Chemistry
1 answer:
sveta [45]2 years ago
6 0

Answer: 4.7432 L

Explanation:

Use stoichiometry: .4235 mol CuCl2 (1 mol I2 / 2 mol CuCl2)(22.4 L / 1 mol I2) = 4.7432 L :)

You might be interested in
Problem PageQuestionSteam reforming of methane ( ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas,
Serhud [2]

The question is incomplete. Her eis the complete question.

Steam reforming methane  (CH4) produces "synthesis gas", a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 125L tank with 20 mol of methane gas and 10 mol of water vapor at 38°C. He then raises the temperature, and when the mixture has come to equilibrium measures the amount of gas hydrogen to be 18 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to significant digits.

Answer: K_{c} = 2.10^{-2}

Explanation: The reaction for steam reforming methane is:

CH_{4} + H_{2}O ⇒ CO_{} + 3H_{2}

To calculate the concentration equilibrium constant, first calculate the molarity (\frac{mol}{L}) of each molecule of the reaction.

At 38°C: At the initial temperature, there no products yet

<u>Molarity of CH4</u>:

CH4 = \frac{20}{125} = 0.16M

<u>Molarity of H20</u>:

H2O = \frac{10}{125} = 0.08M

At final temperature:

<u>Molarity of H2</u>:

H2 = \frac{18}{125} = 0.144M

According to the chemical reaction, the combination of 1 mol of each reagents produces 1 mol of CO and 3 mols of H2, so, for the products, the ratio is 1:3.

<u>Molarity of CO</u>:

CO = \frac{0.144}{3} = 0.048M

For the reagents, the proportion is 1:1, but they had an initial concentration, so, when in equilibrium, the concentration will be:

<u>Molarity of CH4</u>:

CH4 = 0.16 - 0.048 = 0.112M

<u>Molarity of H2O</u>:

H20 = 0.08 - 0.048 = 0.032M

The equilibrium constant is given by:

K_{c} = \frac{[CO][H_{2}]^{3} }{[CH_{4}][H_{2}O ] }

K_{c} = \frac{0.048.0.144^{3} }{0.112.0.032}

K_{c} = 2.10^{-2}

The concentration equilibrium constant for the process is K_{c} = 2.10^{-2}.

4 0
3 years ago
41 g of MgCl^2 is how many moles of magnesium chloride?
kari74 [83]

Answer:

0.43 mol.

Explanation:

  • Knowing that the no. of moles can be calculated using the relation:

<em>no. of moles (n) = mass/molar mass</em>

mass of MgCl₂ = 41.0 g & molar mass of MgCl₂ = 95.211 g/mol.

<em>∴ n = mass/molar mass</em> = (41.0 g)/(95.211 g/mol) = <em>0.43 mol.</em>

6 0
3 years ago
Need help for number 4. do i use the q=mc DELTA T equation or the q=mHfusion?
Natasha2012 [34]
Since it is a phase change, use the mHfusion equation.
7 0
3 years ago
Calculate the mass of 4.55x1024 molecules of sucrose
maxonik [38]

Answer:

2584 g

Explanation:

The molecular formula for sucrose is C₁₂H₂₂O₁₁, which means its molar mass is 342.3 g/mol.

First we<u> convert molecules into moles</u> by using <em>Avogadro's number</em>:

  • 4.55x10²⁴ molecules ÷ 6.023x10²³ mol/molecules = 7.55 mol

Now we <u>convert moles of sucrose into grams</u>, using its<em> molar mass</em>:

  • 7.55 mol * 342.3 g/mol = 2584 g
7 0
3 years ago
How many of the following are compounds?<br> H2O, N2O4, NaOH, MnO2, HF
lukranit [14]
Im pretty sure all of them are compounds

4 0
3 years ago
Read 2 more answers
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