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2 years ago

Dexter collected data from his classmates on whether they prefer hamburgers or hotdogs.

Mathematics

2 answers:

algol132 years ago

6 0

C) More girls than boys prefer hamburgers over hotdogs.

Vedmedyk [2.9K]2 years ago

3 0

Answer:

C) More girls than boys prefer hamburgers over hotdogs.

Step-by-step explanation:

Boy likes hamburgers:

(13 + 8)

= 0.6190 ≈ 62%

Girl likes hamburger:

(12 + 5)

= 0.7059 ≈ 71%

thus,

girls (71 of 100) > boys (62 of 100)

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please answer this question fast and please show all your work because I am locking for how can you do it please

inysia [295]

Option C is the correct values of the relationship between the number of cakes the baker makes and the number of bags of flour uses.

Solution:

Option A: Ratio of cakes baked to bags of flour used

$$\frac{9}{4}, \frac{18}{6}=\frac{3}{1} \text { and } \frac{27}{9}=\frac{3}{1}$

Here the ratios are not same.

So, this option is not true.

Option B: Ratio of cakes baked to bags of flour used

$$\frac{6}{2}=\frac{3}{1}, \frac{12}{4}=\frac{3}{1} \text { and } \frac{18}{6}=\frac{3}{1}$

Here the ratios are same.

So, this option is true.

Option C: Ratio of cakes baked to bags of flour used

$$\frac{4}{9}, \frac{6}{18}=\frac{1}{3} \text { and } \frac{9}{17}$

Here the ratios are not same.

So, this option is not true.

Option D: In this table cakes baked is 6 and the bags of flour is 18.

But a baker made 18 cakes using 6 bags of flour.

So, this option is not true.

Hence option C is the correct values of relationship between the number of cakes the baker makes and the number of bags of flour uses.

6 0

2 years ago

You own 17 CDs. You want to randomly arrange 5 of them in a CD rack. What is the probability that the rack ends up in alphabetic

amid [387]

The probability that all five end up in alphabetical order is; 1/120.

<h3>What is the probability that the rack ends up in alphabetical order?</h3>

To evaluate the given probability; first, the number of possible arrangements is;

17P5 = 742,560 possible arrangements.

However, the chance of an alphabetical order arrangement in each case is; 1 out of 5! possible arrangements.

Hence, we have that the number of possible alphabetical arrangement is; (1/120) × 742,560 = 6188.

Hence, the required probability is; 6188/742,560 = 1/120