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4vir4ik [10]
3 years ago
15

Which shows how we could find the area of a rug that is 6 ft on one side and 3 1/2 ft on the other side?

Mathematics
2 answers:
alex41 [277]3 years ago
3 0
I believe the answer is the last option

hope that helps, God bless!
Anna11 [10]3 years ago
3 0
Think it’s the last one
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What is y+3=4(x-1) in Slope intercept form ?
mina [271]
Y+3=4(x-1)
Y+3=4x-4
-3 -3
Y=4x-7
3 0
3 years ago
Please help with these math questions part 2
NikAS [45]
5).
and
6).
The volume of a sphere is

               (4/3) (pi) (radius)³ .

In #5, the 'pi' is already there next to the answer window.
You just have to come up with the (4/3)(radius³).

Remember that the radius = 1/2 of the diameter.

7).  The volume of a cylinder is

                         (pi) (radius²) (height) .

Divide the juice in the container by the volume of one can,
to get the number of cans he can fill.

8).  The volume of a cone is

                     (1/3) (pi) (radius of the round bottom)² (height) .

He starts with a small cone, he then adds clay to it to make it higher.
The question is:  How much clay does he ADD to the short one,
to make the bigger one ?

Use the formula to find the volume of the short one.
Use the formula again to find the volume of the bigger one.
Then SUBTRACT the smaller volume from the bigger volume.
THAT's how much clay he has to ADD.

Notice that the new built-up cone has the same radius
but more height than the first cone.
_______________________________________

Don't worry if you don't understand this.

The answer will be this number:

 (1/3) (pi) (radius²) (height of the big one minus height of the small one).
6 0
3 years ago
Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+
Hoochie [10]
The vertex form of the equation of a parabola is given by

y-k=a(x-h)^2

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

y-(-2)=a(x-(-12))^2 \\  \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\  \\ y=ax^2+24ax+114a-2 \\  \\ y=x^2+24x+ \frac{114a-2}{a}

For a = 1,

y=x^2+24x+112

<span>The parabola whose minimum is at (−12,−2) is given by the equation y=x^2+ax+b, where a = 24 and b = 112.</span>
8 0
3 years ago
Can someone help me with this please?
AfilCa [17]

Answer:

87

Step-by-step explanation:

14 = Minimum

22 = Lower quartile

32 = Median

87 = Upper quartile

95 = Maximum

8 0
3 years ago
Ok last question i asked was answered by a scam bot so here i go again
Daniel [21]

Answer:

Make 7 jumps, each 0.2 units long. You end at 1.4, which is the product of 7 and 0.2.

Sorry to hear about the bot! Hope this helps!

5 0
2 years ago
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