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Kay [80]
2 years ago
6

Darnell and Lance are both saving money. Darnell currently has $40 and is saving $5 each week. Lance has $25 and is saving $8 ea

ch week.
What week will Darnell and Lance have the same amount of money?

How much will each boy have when they have the same amount of money?

If both boys continue saving at this rate, who will have $100 first
Mathematics
1 answer:
Romashka [77]2 years ago
4 0

Answer:

the answer is 1,203 because your finding the unit price.

Step-by-step explanation:

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Find the percent of the total area under the standard normal curve between the given z-scores. z= -1.10 and z= -0.36
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0987\sqrt{x}   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]
3 0
3 years ago
A trapeziodal pyramid has a volume 2856insquared the height of the pyramid is 24in and the lengths of the 2 two bases of the tra
zalisa [80]
V = 1/3Bh
B = 1/2(b1 + b2)t

V = 1/3[1/2(b1 + b2)t] * h
h = 24
b1 = 13
b2 = 29
t = ?
V = 2856

Substitute:
2856 = 1/3[1/2(13 + 29)t](24)
2856 = 1/6(42)(24)t
2856 = 7(24)t
2856 = 168t
t = 2856/168 = 17 in height of the trapeziod
8 0
3 years ago
Hassan's backyard swimming pool is 30 feet long, 20 feet wide, and 5 feet deep. there are 7.5 gallons of water in 1 cubic foot.
cricket20 [7]
Find how many cubic feet
cubic feet=length times width times height for rectangle prism

volume=30 times 20 times 5=3000 cubic feet

7.5 per 1 cubic feet
times 3000
22500 gallons
3 0
3 years ago
A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min
sesenic [268]
A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})
\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}
A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4

We're given that A(0)=30. Multiply both sides by the integrating factor e^{t/100}, then

e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4
\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4
e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C
A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}

Given that A(0)=30, we have

30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02

so the amount of salt in the tank at time t is

A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}
3 0
3 years ago
Name the angle relationship. Find the measure of angle b.
Viefleur [7K]

Answer:

Vertical angels, b is the same as the opposite angle, 86

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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