When copper (ii) carbonate is heated if forms copper (ii) oxide and carbon dioxide?
1 answer:
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Given :
Rate = 75 m 1 s×60 s 1 min×1 h 60 m.
To Find :
Correct answer after conversion.
Solution :
We know, 1 min = 60 sec.
1 hour = 60 min = 60×60 sec = 3600 sec.
Putting value of min and hour in seconds , we get :
Hence, this is the required solution.