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Snowcat [4.5K]
3 years ago
8

What group is the element NITROGEN in? 1 Group 4 2 Group 5 3 Group 2 4 Group 8

Chemistry
2 answers:
Butoxors [25]3 years ago
3 0

Answer:

r7ñopdyiwriduwyzgpxpo

nika2105 [10]3 years ago
3 0
Answer:
Group 5

Explanation:
It has 3- charge
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The reduction of alkyne to an alkene in the first step allows the best reagent to be chosen for each subsequent step.

Describe reagents.

A reagent is merely an essential component of a chemical reaction, it should be mentioned. It is an ingredient that speeds up the reaction.

With H2 and Lindlar's catalyst, an alkyne is reduced to alkene as the initial step in this process. Alkene will then be brominated to produce allyl bromide as the next step.

In this instance, the required allyl alcohol will be produced via the reaction of allyl bromide with NaOH.

Learn more about reagent here brainly.com/question/23342137

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A scientist discovers a deep bowl-like divot under the ocean off the coast of eastern Mexico that is many kilometers across. The
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3 years ago
Read 2 more answers
Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

\%C_E = \frac{200}{74}\%

\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

5 0
2 years ago
May you please help if you don’t know scroll it you’re 100% thank you
grandymaker [24]

Answer: rise earlier and set later

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5 0
3 years ago
How many grams of methionine (MW = 149.21) are needed to make 20 mL of a 150 mM solution?
Leni [432]

Answer:

0.45 g

Explanation:

Step 1: Given data

  • Molar mass of methionine (M): 149.21 g/mol
  • Volume of the solution (V): 20 mL
  • Concentration of the solution (C): 150 mM

Step 2: Calculate the moles of methionine (n)

We will use the following expression.

n = C × V

n = 150 × 10⁻³ mol/L × 20 × 10⁻³ L

n = 3.0 × 10⁻³ mol

Step 3: Calculate the mass of methionine (m)

We will use the following expression.

m = n × M

m = 3.0 × 10⁻³ mol × 149.21 g/mol

m = 0.45 g

7 0
3 years ago
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