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IRINA_888 [86]
3 years ago
5

Find an input that yield an output of -1 rule y=-2x+33

Mathematics
1 answer:
djyliett [7]3 years ago
3 0

Input (x-value)

Output (y-value)

You need to find the x-value that produces a y-value of -1. Since you know:

y = -1       Use the rule, and substitute/plug this into the equation

y = -2x + 33       Plug in -1 for "y" in the equation since y = -1

-1 = -2x + 33        Subtract 33 on both sides

-1 - 33 = -2x + 33 - 33

-34 = -2x      Divide -2 on both sides to get "x" by itself

\frac{-34}{-2}=\frac{-2x}{-2}

17 = x

An input of 17 yields an output of -1

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How do you solve this question? Any help appreciated!
fiasKO [112]
\bf \displaystyle \int\limits_{1}^{e}\cfrac{1}{t}\cdot dt\\\\
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\textit{doing substitution}\\\\
u=\cfrac{1}{t}\implies u=t^{-1}\implies \cfrac{du}{dt}=-t^{-2}\implies \cfrac{du}{dt}=-\cfrac{1}{t^2}\\\\\\ -t^2du=dt\\\\
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\displaystyle \int\limits_{1}^{e}u\cdot -t^2du\impliedby \textit{now, let's do some substitution on the "t"}\\\\
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\bf u=\cfrac{1}{t}\implies t=\cfrac{1}{u}\implies t^2=\cfrac{1^2}{u^2}\implies t^2=\cfrac{1}{u^2}\\\\
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\displaystyle \int\limits_{1}^{e}u\cdot -\cfrac{1}{u^2}\cdot du\implies -1\int\limits_{1}^{e}\cfrac{1}{u}\cdot du\implies \left. -ln|u| \cfrac{}{}\right]_1^e

\bf \left. -ln\left( \frac{1}{t} \right) \cfrac{}{}\right]_1^e\implies 
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8 0
3 years ago
What's the slope between (-2, 8) and (4, 20)
Inessa [10]

Answer:

2

Step-by-step explanation:

8 - 20 = -12

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5 0
2 years ago
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denpristay [2]
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8 0
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Which zero pair could be added to the function fon) = x2 + 12x + 6 so that the function can be written in vertex form?
Oksanka [162]

ANSWER

36,-36

EXPLANATION

The given function is:

f(x) =  {x}^{2}  + 12x + 6

To write this function in vertex form;

We need to add and subtract the square of half the coefficient of x.

The coefficient of x is 12.

Half of it is 6.

The square of 6 is 36.

Therefore we add and subtract 36.

Hence the zero pair is:

36, -36.

The correct answer is D.

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REY [17]

Answer:

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Step-by-step explanation:

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