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jeka57 [31]
3 years ago
15

How to solve wx=x+5, tw=4x+5: tx

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0
Hello : 
wt = wx +xt
xt = wt - wx=(4x+5) - (x+5) = 3x
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a company’s stock was selling at $24 a share a month later it was selling at $30 a share what is the percent gain
Arisa [49]
Mmm like 4 if to 30 in total but I ain’t know out 100
4 0
3 years ago
110% of 90 is what number a ?<br><br>? = 110 over 100<br>please help​
densk [106]

Answer:

90 is the orrect answer because I said so

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
HELP ME PLEASE ASAP?!?What is the value of y?
Snezhnost [94]
Answer: y = 57°

Explanation: 180-114 = 66°

A triangle has a total of 180° so 180-66 = 114

114 / 2 = 57° (because angles y and y have the same value)

Hope this helps :)
7 0
3 years ago
How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
3 years ago
Help quick pls lol I’m doing my homework and it has to be due in 5 minutes
snow_tiger [21]

Answer:

7

Step-by-step explanation:

hurry!

3 0
3 years ago
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