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Ray Of Light [21]
3 years ago
9

What is the minimum number of vectors lying in the same plane required to givs zero resulant

Physics
2 answers:
alexgriva [62]3 years ago
7 0
Well the trivial answer is zero, since there is indeed a "zero vector". Assuming you aren't allowed to use the zero vector you would need at least two. They would be antiparallel and of equal magnitude. (That is be pointing in opposite directions and have the same length)
scZoUnD [109]3 years ago
7 0

Answer: Minimum number of non-equal vectors in a plane required to give zero resultant is three.

Explanation:

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Answer:

C. 590 mph

\vert v_{cj}\vert=589.49\ mph

Explanation:

Given:

  • velocity of jet, v_j=500\ mph
  • direction of velocity of jet, east relative to the ground
  • velocity of Cessna, v_c=150\ mph
  • direction of velocity of Cessna, 60° north of west

Taking the x-axis alignment towards east and hence we have the velocity vector of the jet as reference.

Refer the attached schematic.

So,

\vec v_j=500\ \hat i\ mph

&

\vec v_c=150\times (\cos120\ \hat i+\sin120\ \hat j)

\vec v_c=-75\ \hat i+75\sqrt{3}\ \hat j\ mph

Now the vector of relative velocity of Cessna with respect to jet:

\vec v_{cj}=\vec v_j-\vec v_c

\vec v_{cj}=500\ \hat i-(-75\ \hat i+75\sqrt{3}\ \hat j )

\vec v_{cj}=575\ \hat i-75\sqrt{3}\ \hat j\ mph

Now the magnitude of this velocity:

\vert v_{cj}\vert=\sqrt{(575)^2+(75\sqrt{3} )^2}

\vert v_{cj}\vert=589.49\ mph is the relative velocity of Cessna with respect to the jet.

8 0
3 years ago
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Answer:

21.55 m

Explanation:

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3 years ago
The energy goes from _____ to the _____ above it.
Artist 52 [7]

Answer:

The energy goes from <u>the ground state</u> to <u>the excited states</u> above it.

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Answer:

The current through a branch is also called the branch current. The current supplied by the battery in a parallel circuit splits at one or more branch points. All of the current entering a branch point must exit again. This rule is known as Kirchhoff's current law

Explanation:

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3 years ago
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