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Airida [17]
4 years ago
7

Can someone help me?

Physics
2 answers:
valentinak56 [21]4 years ago
7 0
For #7 I would say yes because she got more evidence showing what butterflies and moths like about different colored flowers.
vlabodo [156]4 years ago
6 0
1. Science.
2. evidence
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Calculate the net force experienced by Mr. Ferrari if he has a mass of 100 kg and an acceleration of 3.5 m/s/s.
saveliy_v [14]
The answer is 350. the formula for net force is f=ma which means you multiply the mass times he acceleration. 100 times 3.5 is 350
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3 years ago
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In a position time graph, a curved line represents: acceleration no movement constant velocity
Mumz [18]

Answer:

acceleration or a deceleration

Explanation:

The gradient of a position -  time graph represent the velocity.

a straight line indicate a constant velocity (gradient ≠ 0)

when it is a parallel line to the time axis , it indicated no movement

when it is a curved line it indicates a changing velocity (either acceleration or a deceleration) as mentioned in the graph

4 0
3 years ago
Three 10-cm-long rods form an equilateral triangle. Two of the rods are charged to + 19 nC, the third to - 19 nC.What is the ele
Sveta_85 [38]
<span>We calculate the electric field as follows:
r = </span>√<span>(3)/6 x 19 cm = .05484 m 
The angle for the triangle would be 30 on each side.
tan(30) = r/(L/2) 

E' = kQ/{r*sqrt[(L/2)^2 + r^2]} = (8.99e9 x 15e-9) / {.05484 * sqrt[(.19/2)^2 + .003]}
</span>E' <span>= 22413 N/C
The value above is the electric field strength for a single rod at the center. 

|E'| = 22413 N/C 
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5 0
3 years ago
A potter's wheel has the shape of a solid uniform disk of mass 13.0 kg and radius 1.25 m. It spins about an axis perpendicular t
Fittoniya [83]

Answer:10.82 kg-m^2

Explanation:

Given

Mass of solid uniform disk M=13 kg

radius of disk r=1.25 m

mass of lump m=1.7 kg

distance of lump from axis r_0=0.63

Moment of inertia is the distribution of mass from the axis of rotation

Initial moment of inertia of disk I_1=\frac{Mr^2}{2}

I_1=\frac{13\times 1.25^2}{2}=10.15 kg-m^2

Final moment of inertia I_f=Moment of inertia of disk+moment of inertia of lump about axis

I_f=\frac{Mr^2}{2}+mr_0^2

I_f=10.15+1.7\times 0.63^2

I_f=10.15+0.674

I_f=10.82 kg-m^2

3 0
4 years ago
Why are force fields used to describe magnetic force?
Illusion [34]

Answer:

If I'm not working I think the answer is C.

7 0
4 years ago
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