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frozen [14]
3 years ago
9

A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.290 Hz. The pendulum ha

s a mass of 2.40 kg, and the pivot is located 0.300 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point.
Physics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

1.4584 kgm^2

Explanation:

Time period of a physical pendulum is given by T=2Π\sqrt{\frac{I}{mgd}}

Here f=0.290 so T=\frac{1}{F}=\frac{1}{0.29}=3.44827

Mass =2.40 kg

d=0.300 m

g =9.8 msec^2

So 3.448=2\times \pi \sqrt{\frac{I}{2.4\times 9.81\times 0.300}}=1.4584  kg-m^2

So the moment of inertia of the pendulum about the pivot point will be 1.4584 kg-m^2

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What is the self-inductance of a solenoid 30.0 cm long having 100 turns of wire and a cross-sectional area of 1.00 × 10-4 m2? (μ
madreJ [45]

Answer:

L=4.19*10^{-6}H

Explanation:

The self-inductance of a solenoid is defined as:

L=\frac{\mu N^2A}{l}

Here \mu_0 is the the permeability of free space, N is the number of turns in the solenoid, A is the cross-sectional area os the solenoid and l its length. We replace the given values to get the self-inductance:

L=\frac{4\pi*10^{-7}\frac{T\cdot m}{A}(100)^2(1*10^{-4}m^2)}{30*10^{-2}m}\\L=4.19*10^{-6}H

4 0
4 years ago
If an oxygen molecule traveling at the rms speed bounces back and forth between opposite sides of a cubical vessel of 0.10 m on
Alisiya [41]

Answer:

1.25x10^-19N

Explanation:see attached file pls

5 0
3 years ago
Choose the 200 kg refrigerator. Set the applied force to 400 N (to the right). Be sure friction is turned off.What is the net fo
White raven [17]
So, there should be two forces acting on the refrigerator: the applied force and the friction force.

The question mentioned that the friction force was set to zero, so the only effective force now would be the applied force.

We have an applied force of 400 N to the right, this means that:
<span>The magnitude of the net force is 400, directed to the right.</span>
3 0
3 years ago
Read 2 more answers
At 2:00 p.m. a car's speedometer reads 30 mi/h. At 2:30 p.m. it reads 50 mi/h. Show that at some time between 2:00 and 2:30 the
Gelneren [198K]

Answer:

The acceleration is exactly 40 mi/h² as shown

Explanation:

Given;

initial velocity of the car, u = 30 mi/h

final velocity of the car, v = 50 mi/h

change in velocity, ΔV = v - u

                               ΔV = 50 mi/h - 30 mi/h = 20 mi/h

initial time, t₁ = 2:00 PM

final time, t₂ = 2:30 PM

Change in time, Δt = t₂ - t₁

                           Δt = 2: 30 - 2:00 = 30 mins  = 0.5 hour

Acceleration is given as change in velocity per change in time;

a = ΔV /  Δt

a = \frac{20 \ mi/h}{0.5 \ h}\\\\a = 40 \ mi/h^2 \ (shown)\\\\

Therefore, the acceleration is exactly 40 mi/h² as shown.

6 0
3 years ago
An unknown mass of each substance, initially at 25.0 ∘C, absorbs 1920 J of heat. The final temperature is recorded. Find the mas
zhannawk [14.2K]

Answer: mass for Pyrex glass 84.21g

mass for sand 61.6g

mass for ethanol 41.32g

mass for water 62.07g

Explanation

By definition specific heat is the amount of heat required to change the temperature of 1 kg mas by 1°C

Q=mcΔT is formula for specific heat

Q is heat transfer

m is mass

ΔT is change in temperature

c   is specific heat

c of Pyrex glass= 0.75 j/g°C

c of sand = 0.84 j/g°C

c of ethanol= 2.42 j/g°C

c of water = 4.18 j/g°C

now we will make M(mass) the subject, so equation becomes

m=Q/cΔT

for

pyrex glass T<em>f=</em>55.4°C

m=1920/(55.4-25)*0.75

m=84.21g {after cutting J(joules) and °C we are left with g(grams)}

for

sand T<em>f</em>=62.1°C

m=1920/(62.1-25)*0.84

m=61.6g {after cutting J(joules) and °C we are left with g(grams)}

for

ethanol T<em>f</em>=44.2°C

m=1920/(44.2-25)*2.42

m=41.32g  {after cutting J(joules) and °C we are left with g(grams)}

for

water T<em>f=</em>32.4°

m=1920/(32.4-25)*4.18

m=62.07g  {after cutting J(joules) and °C we are left with g(grams)}

i hope you understand the solution, thank you.

7 0
3 years ago
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