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3 years ago

I WILL GIVE BRAINLIEST....Determine the value of F...

Physics

1 answer:

aleksley [76]3 years ago

6 0

F should be 10. If The Whole top is 50cm, then we should subtract 10n and 30n which gives us 10.

Or it could be 15 if both top and bottom are 25. 10+15= 25.

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A Dodge Stealth is driving at 70 mph on a highway. It passes a BMW going the same direction. The BMW is moving 7 mph backward re

Tasya [4]

A Dodge Stealth is driving at 70 mph on a highway. It passes a BMW going the same direction. The BMW is moving 7 mph backward relative the Dodge. 63 mph is the velocity of the BMW

Answer: Option A

<u>Explanation:</u>

Given is the speed of the dodge stealth as 70 mph passing by the BMW moving with 7 mph relative to Dodge. Thereby, to calculate the velocity of BMW, relative velocity concept has to be employed.

As we know that the relative velocity tells us about relative velocity of mobile reference system as the difference or sum of the initial reference system.

Therefore,

velocity of the BMW = $v_{b}$

Velocity of the dodge = $v_{d}$

Velocity of the BMW with respect to dodge = $V_{b d}$

As per the formula,

$v_{b d}=v_{b}-v_{d}$

$v_{b} = v_{d} + v_{b d} = 70 + (-7) = 70 - 7 = 63 \mathrm{mph}$

5 0

3 years ago

Which factors affect the gravitational force between objects? Check all that apply.

drek231 [11]

Explanation:

distance between both objects and masses of the objects

4 0

3 years ago

Read 2 more answers

Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive

Setler [38]

Answer:

The mass of the massive object at the center of the Milky Way galaxy is $3.44\times10^{37}\ Kg$

Explanation:

Given that,

Diameter = 10 light year

Orbital speed = 180 km/s

Suppose determine the mass of the massive object at the center of the Milky Way galaxy.

Take the distance of one light year to be 9.461×10¹⁵ m. I was able to get this it is 4.26×10³⁷ kg.

We need to calculate the radius of the orbit

Using formula of radius

$r=\dfrac{d}{2}$

$r=\dfrac{15\times9.461\times10^{15}}{2}$

$r=7.09\times10^{16}\ m$

We need to calculate the mass of the massive object at the center of the Milky Way galaxy

Using formula of mass

$M=\dfrac{v^2r}{G}$

Put the value into the formula

$M=\dfrac{(180\times10^3)^2\times7.09\times10^{16}}{6.67\times10^{-11}}$

$M=3.44\times10^{37}\ Kg$

Hence, The mass of the massive object at the center of the Milky Way galaxy is $3.44\times10^{37}\ Kg$

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3 years ago

You tie a cord to a pail of water, and you swing the pail in a vertical circle of radius 0.600 m. what minimum speed must you gi

omeli [17]

Hrre si yen nserrras

6 0

3 years ago

An astronomer is observing a star which puzzles her. The lines in the star's spectrum indicates that the star is very hot and sh

Firlakuza [10]

Answer:

the stars which are red in color are cool.

Explanation:

The stars which has reddish color are cool in nature while those stars which has white and blue in color are very hot in nature. The stars change its color when they becomes hotter , first the star color reddish when they are cool but with increasing temperature it changes the color from reddish to orange then yellow. After yellow it turns green and finally get blue color when the stars are very very hot.

5 0

3 years ago

I WILL GIVE BRAINLIEST....Determine the value of F...​

I WILL GIVE BRAINLIEST....Determine the value of F...