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victus00 [196]
3 years ago
14

Find the amount of molding needed for a 10' x 7' floor.

Mathematics
1 answer:
beks73 [17]3 years ago
6 0
To calculate the amount of molding needed for 10 feet by 7 feet floor, we need to assume some parameters. We can assume that the floor is a regular rectangle with sides 10 and 7 feet. Then the molding needed will be the area of the rectangular floor:

A = l x w
A = 10 feet x 7 feet
A = 70 square feet. 
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A number cube is labeled 1 to 6. Rachel will roll the number cube 500 times and record her results. About how many times could R
rosijanka [135]

Answer:

250

Step-by-step explanation:

there is 3 odds and 3 evens

7 0
2 years ago
Get the product using FOIL method: (x+2)(x+3)
emmasim [6.3K]

Answer:

x² + 5x + 6

Step-by-step explanation:

Foil means first, outside, inside, last

First: (x+2)(x+3)

x × x = x²

Inside: (x+2)(x+3)

x × 3 = 3x

Ouside: (x+2)(x+3)

2 × x = 2x

Last: (x+2)(x+3)

2 × 3 = 6

adding them together:

x² + 3x + 2x + 6 = x² + 5x + 6

8 0
2 years ago
Solve the equation the square of 2x + 1 equals the square of x + 4
gavmur [86]
I am sorry this is where I can get too.

8 0
3 years ago
A delivery truck driver charges a fixed base price of $6 for 2 miles.
stiv31 [10]

Answer:

Option B.

Step-by-step explanation:

It is given that a delivery truck driver charges a fixed base price of $6 for 2 miles.

After 2 miles, he charges an additional $2 for every mile and after 6 miles, he charges an additional $4 for every mile.

We need to describe the cost of the delivery truck between 1 mile and 2 miles.

In the given graph x-axis represents the distance in miles and y-axis represents the cost in dollars.

From the given graph it is clear that the value of function is constant between x=1 and x=2.

It means the cost of the delivery truck between 1 mile and 2 miles is constant.

Therefore, the correct option is B.

5 0
3 years ago
Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i
Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) \frac{20i+21}{29}

(c) i

Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

(b) We have given expression \frac{5-2i}{5+2i}

After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

5 0
3 years ago
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