Answer:
Percent yield of reaction is 75%.
Explanation:
Given data:
Moles of A = 2.0 mol
Moles of B = 4.0 mol
Moles of C formed = 1.8 mol
Percent yield of reaction = ?
Solution:
Chemical equation:
2A + 5B → 3C + D
We will compare the moles of A and B with C from balance chemical equation.
A : C
2 : 3
B : C
5 : 3
4 : 3/5×4 = 2.4 mol
Number of moles of C formed by 4 moles B are less thus B is limiting reactant and will limit the yield of C.
Percent yield:
Percent yield = actual yield /theoretical yield × 100
Percent yield = 1.8 mol / 2.4 × 100
Percent yield =75%
Molar heat of vaporization is defined as the heat absorbed by one mole of substance to convert from liquid to gas.
<h3>How do you calculate the heat of vaporization?</h3>
The formula used to calculate the heat of vaporization is:

Where,
Q = Amount of Heat
n = number of moles of a substance
molar enthalpy of fusion
Now, to calculate the moles of methane:

Moles = 3.425 mol
Now, 1 mol of methane absorbs = 8.53 KJ
3.425 mol of methane absorbs = 
Thus, the energy is absorbed till the methane vaporizes at its boiling point is 29.1 KJ.
Learn more about <u>vaporization </u>here:
brainly.com/question/2491083
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