The answer : protons and neutrons
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<u>Answer:</u> The standard enthalpy of formation of is -92.7 kJ/mol
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate enthalpy change is of a reaction is:
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the standard enthalpy of formation of is -92.7 kJ/mol
Answer:
1. Electronic configuration of sulphide ion S²¯ (18) => 1s² 2s²2p⁶ 3s²3p⁶
2. Ar
Explanation:
1. S²¯ simply indicates that the sulphur atom (S) has gained two extra electrons.
Thus we shall write electron configuration of sulphur (S) and sulphide ion (S²¯) as follow:
The electronic configuration of S²¯
S (16) => 1s² 2s²2p⁶ 3s²3p⁴
S²¯ (18) => 1s² 2s²2p⁶ 3s²3p⁶
2. Determination of the noble gas element that has the same electronic configuration as S²¯.
This is illustrated below:
Sulphur (S) has 16 electrons while the sulphide ion (S²¯) has extra 2 electrons making it to have a total electron of 18. Observing the elements in the periodic table, only Argon has 18 electrons with electronic configuration as:
Ar (18) => 1s² 2s²2p⁶ 3s²3p⁶
Therefore, sulphide ion (S²¯) has the same electronic configuration as Argon (Ar).
Answer:
NADPH
Explanation:
because it is in a dark stage
Answer:
.6mol/L
Explanation:
molarity = number of moles / volume of solvent (in L)
750mL / 1000mL/L = .75L
M = .450mol / .75L
M = .6mol/L