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LiRa [457]
3 years ago
15

(34.6785 x 5.39) + 435.12

Chemistry
2 answers:
Alex73 [517]3 years ago
6 0

Hope I helped


622.037115

Shalnov [3]3 years ago
5 0
To solve this, we should follow order of operations. To start, we should multiply the values inside of the parentheses.

(34.6785*5.39)+435.12
186.917115+435.12

Now, we should add the 2 values we are left with together.

 186.917115
<span><u>+435.120000</u>
</span>  622.037115

Using the math above, we can see that this expression is equal to 622.037115.
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Write a balanced chemical equation for the synthesis of ammonia from its elements including the word energy as a product
Katen [24]
Ammonia synthesis can be done by Haber process. N₂ gas and H₂ gas are used as the reactants. <span>The balanced reaction equation is
</span>N₂(g) + 3H₂(g) ⇄ 2NH₃(g) + energy

This is a reversible process and the conditions as follows,
1. Pressure
should be 150 - 200 atm
2. Temperature
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5 0
3 years ago
The Law of Conservation of Matter describes how mass is not lost during a chemical reaction.
weeeeeb [17]

False, it states that matter can be nether created nor destroyed

7 0
3 years ago
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You have a substance with a length of 2 cm, width of 3 cm, and a height of 4 cm. Its density is known to be .5 g/cm3. What is th
otez555 [7]

Explanation:

They are related by the the density triangle.

Explanation:

They are related by the the density triangle.

mcdn1.teacherspayteachers.com

d =

m

V

m = d×V

V =

m

d

DENSITY

Density is defined as mass per unit volume.

d =

m

V

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =

m

V

=

433

g

200

c

m

³

= 2.16 g/cm³

MASS

d =

m

V

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×

1.11

g

1

m

L

= 555 g

VOLUME

d =

m

V

We can rearrange this to get the expression for the volume.

V =

m

d

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×

1000

g

1

k

g

= 14 830 g

Step 2: Calculate the volume.

V =

m

d

= 14 830 g ×

1

c

m

³

19.32

g

= 767.6 cm³

5 0
2 years ago
Which of the following are strongly hydrogen bonded in the liquid phase? A) nitrilesB) esters C) secondary amides D) acid chlori
-Dominant- [34]

Answer: Option (C) is the correct answer.

Explanation:

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Therefore, the hydrogen atom will be more strongly held by the electronegative oxygen atom. As a result, there will be  strongly hydrogen bonded in the liquid phase of secondary amide.

Whereas chemical formula of nitriles is RCN, ester is RCOOR' and acid chlorides are RCOCl. As no hydrogen bonding occurs in any of these compounds because hydrogen atom is not being attached to an electronegative atom.

Thus, we can conclude that secondary amides are strongly hydrogen bonded in the liquid phase.

6 0
3 years ago
1. How many protons does 14/6 C contain? What element is this?
Harman [31]

Answer:

It has 6 protons and its Carbon 14

Explanation:

3 0
3 years ago
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