Question

The final exam grade of a mathematics class has a normal distribution with mean of 81 and standard deviation of 6.6. If a random sample of 40 students selected from this class, then what is the probability that the average final exam grade of this sample is between 77 and 82? Answer: (round to 4 decimal places)

Answer 1

Answer:

The probability that the average final exam grade of this sample is between 77 and 82

P(77≤ x⁻≤ 82 =  0.8315 or 83%

Step-by-step explanation:

Step(i):-

Given random sample size 'n' = 40

Mean of the normal distribution = 81

Standard deviation of normal distribution = 6.6

Let x₁⁻ = 77

$Z_{1} = \frac{x_{1} -mean }{\frac{S.D}{\sqrt{n} } } = \frac{77-81}{\frac{6.6}{\sqrt{40} } }$

Z₁ = -3.83

Let x₂⁻ = 77

$Z_{2} = \frac{x^{-} _{2} -mean }{\frac{S.D}{\sqrt{n} } } = \frac{82-81}{\frac{6.6}{\sqrt{40} } }$

Z₂ = 0.958

The probability that the average final exam grade of this sample is between 77 and 82

P(77≤ x≤ 82) = P( -3.83 ≤x≤0.958)

                    = A( 0.958) + A(3.83)

                   = 0.3315 + 0.4995

                   = 0.8315

The probability that the average final exam grade of this sample is between 77 and 82  = 0.8315 or 83%